A particle with a charge of q = 12.0 μC travels from the origin to the point (x, y) = (20.0 cm, 50.0 cm) in the presence of a uniform electric field E = 2901 V/m. Determine the following (a) the change in the electric potential energy (in J) of the particle-field system J (b) the electric potential difference (in V) through which the particle moves
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- A particle with a charge of q = 12.0 µC travels from the origin to the point (x, y) = (20.0 cm, 50.0 cm) in the presence of a uniform electric field E = 210î V/m. Determine the following. (a) the change in the electric potential energy (in J) of the particle-field system (b) the electric potential difference (in V) through which the particle moves VA small object with a charge of q = 12.0 µC travels from the origin to the point (x, y) = (20.0 cm, 50.0 cm) in the presence of a uniform electric field E = 2701 V/m. Determine the following. (a) the change in the electric potential energy (in J) of the object-field system (b) the electric potential difference (in V) through which the object moves V Need Help? Read ItThe graph in the figure shows the variation of the electric potential V as a function of position x. V (volts) 4 AA 4 2 4 -8 -6 -2.0 V/m +2.0 V/m The x-component of the electric field at x = -3 m is given by: -0.5 V/m -0.67 V/m 6 +0.67 V/m →x (meters) 8
- A particle of mass 6.4 g and charge 21.5 µC is moving in an electric potential field V(x, y) = C₁ x - C₂ ⋅ y² + c3・y.x², C1 • where c₁= 65 V/m, c2= 45 V/m², and c3= 20 V/m³. Find the electric field acting on the particle as a function of its position. Use V/m and meters for the units, but do not put them explicitly in Ē(x, y). The x-compoment of the E-field, Ex(x,y) = Units Select an answer ✓ The y-compoment of the E-field, Ey(x, y) = What is the magnitide of the particle's acceleration at x = 1 m and y = -1 m? The acceleration, a = Units Select an answer ✓ Units Select an answer ✓An electron moving parallel to the x axis has an initial speed of 5.18 x 106 m/s at the origin. Its speed is reduced to 1.68 x 105 m/s at the point x = 2.00 cm. (a) Calculate the electric potential difference between the origin and that point. Volts (b) Which point is at the higher potential? O the origin O the point x = 2.00 cm O both have the same potentialOver a certain region of space, the electric potential is V = 4x - 5x²y + 8yz². (a) Find the expressions for the x, y, z components of the electric field over this region. (Use any variable or symbol stated above as necessary.) Ex Ey Ez = = = (b) What is the magnitude of the field at the point P that has coordinates (1.00, 0, -6.00) m? N/C
- Determine the magnitude of an electric field at a point in space given by r = (1.00 m i, 1.50 m j, -1.00 m k) if the electric potential is given by where x, y, z are in meters and V in volts.A particle with a charge of q = 11.0 µC travels from the origin to the point (x, y) = (20.0 cm, 50.0 cm) in the presence of a uniform electric field E = 250î V/m. Determine the following. (a) the change in the electric potential energy (in J) of the particle-field system (b) the electric potential difference (in V) through which the particle moves VA particle has a charge of +3.50 µC and moves from point A to point B, a distance of 0.130 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +9.30 x 10-4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the electric field that the particle experiences. (a) Number i (b) Number Units Units
- A proton is acted on by an uniform electric field of magnitude 233 N/C pointing in the negative x direction. The particle is initially at rest. (a) In what direction will the charge move? -x direction A (b) Determine the work done by the electric field when the particle has moved through a distance of 3.55 cm from its initial position. J (c) Determine the change in electric potential energy of the charged particle. (d) Determine the speed of the charged particle. 3.85 Consider applying the conservation of energy. m/sA proton is acted on by an uniform electric field of magnitude 203 N/C pointing in the negative y direction. The particle is initially at rest. (a) Determine the work done by the electric field when the particle has moved through a distance of 3.65 cm from its initial position.(b) Determine the change in electric potential energy of the charged particle. (c) Determine the speed of the charged particle.A proton is acted on by an uniform electric field of magnitude 363 N/C pointing in the negative y direction. The particle is initially at rest. (a) In what direction will the charge move? (b) Determine the work done by the electric field when the particle has moved through a distance of 2.95 cm from its initial position. (in Joules)(c) Determine the change in electric potential energy of the charged particle. (J)(d) Determine the speed of the charged particle. (m/s)