A particle that carries a net charge of –41.8 µC is held in a constant electric field that is uniform over the entire region. The electric field vector is oriented 55.2° clockwise from the vertical axis, as shown in the figure. If the magnitude of the electric field is 9.82 N/C, how much work is done by the electric field as the particle is made to move a distance of d = 0.756 m straight up? work: J What is the potential difference AV between the particle's initial and final positions?
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![A particle that carries a net charge of -41.8 µC is held in a
constant electric field that is uniform over the entire region.
The electric field vector is oriented 55.2° clockwise from the
vertical axis, as shown in the figure. If the magnitude of the
electric field is 9.82 N/C, how much work is done by the
electric field as the particle is made to move a distance of
d = 0.756 m straight up?
d
55.2°
work:
What is the potential difference AV between the particle's
initial and final positions?
AV =
V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe799f64b-1f0b-4ff1-9ee3-5090ddf07729%2Ff28d226c-bcb6-46b6-8342-10f7d848c9fa%2Fnf9iasq_processed.png&w=3840&q=75)
![](/static/compass_v2/shared-icons/check-mark.png)
Charge q = -41.8=-41.8
=55.2
The electric field E = 9.82 N/C
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