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A particle of mass m in a rectangular box with a fixed volume has ground state energy k2 E(x, y) 1 1 (* > 0, y > 0), = 8m y? 64 where k is a physical constant. Show that the ground state energy is minimum when x = y = 2.

A particle of mass m in a rectangular box with a fixed volume has ground state energy k2 E(x, y) 1 1 (* > 0, y > 0), = 8m y? 64 where k is a physical constant. Show that the ground state energy is minimum when x = y = 2.

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A particle of mass m in a rectangular box with a fixed volume has ground state energy k2 E(x, y) 1 (* > 0, y > 0), 8m r2 y? 64 where k is a physical constant. Show that the ground state energy is minimum when x = y = 2.
Transcribed Image Text:A particle of mass m in a rectangular box with a fixed volume has ground state energy k2 E(x, y) 1 (* > 0, y > 0), 8m r2 y? 64 where k is a physical constant. Show that the ground state energy is minimum when x = y = 2.
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