A particle of mass m in a rectangular box with a fixed volume has ground state energy k2 E(x, y) 1 1 (* > 0, y > 0), = 8m y? 64 where k is a physical constant. Show that the ground state energy is minimum when x = y = 2.
A particle of mass m in a rectangular box with a fixed volume has ground state energy k2 E(x, y) 1 1 (* > 0, y > 0), = 8m y? 64 where k is a physical constant. Show that the ground state energy is minimum when x = y = 2.
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![A particle of mass m in a rectangular box with a fixed volume has
ground state energy
k2
E(x, y)
1
(* > 0, y > 0),
8m
r2
y?
64
where k is a physical constant. Show that the ground state energy is
minimum when x = y = 2.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5de9b1a7-ce04-43f5-87d9-4de3e25f8076%2Fb1cdac07-621d-4752-9469-e83026a4d9cf%2Fz416p3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A particle of mass m in a rectangular box with a fixed volume has
ground state energy
k2
E(x, y)
1
(* > 0, y > 0),
8m
r2
y?
64
where k is a physical constant. Show that the ground state energy is
minimum when x = y = 2.
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