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A 280-kg load is lifted 22.0 m vertically with an acceleration a=0.140 g by a single cable.

A 280-kg load is lifted 22.0 m vertically with an acceleration a=0.140 g by a single cable.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Can i get help with these questions please

### Part A **Determine the tension in the cable.** You are required to express your answer to three significant figures and include the appropriate units. - **Equation:** \[ F_T = \text{Value} \quad \text{Units} \] Input fields are provided for entering the value and units. You can use the following tools: - Templates (for inserting mathematical symbols and formatting equations) - Symbols (for additional special characters) - Utility buttons for undo, redo, reset, and help with keyboard shortcuts. Submit your answer using the "Submit" button or request a solution using the "Request Answer" link. --- ### Part B **Determine the net work done on the load.** You are required to express your answer to three significant figures and include the appropriate units. - **Equation:** \[ W_{\text{net}} = \text{Value} \quad \text{Units} \] Similar input fields are provided for entering the value and units. Utilize the same tools for equation formatting and character insertion as in Part A. Submit your answer using the "Submit" button or request a solution using the "Request Answer" link.
Transcribed Image Text:### Part A **Determine the tension in the cable.** You are required to express your answer to three significant figures and include the appropriate units. - **Equation:** \[ F_T = \text{Value} \quad \text{Units} \] Input fields are provided for entering the value and units. You can use the following tools: - Templates (for inserting mathematical symbols and formatting equations) - Symbols (for additional special characters) - Utility buttons for undo, redo, reset, and help with keyboard shortcuts. Submit your answer using the "Submit" button or request a solution using the "Request Answer" link. --- ### Part B **Determine the net work done on the load.** You are required to express your answer to three significant figures and include the appropriate units. - **Equation:** \[ W_{\text{net}} = \text{Value} \quad \text{Units} \] Similar input fields are provided for entering the value and units. Utilize the same tools for equation formatting and character insertion as in Part A. Submit your answer using the "Submit" button or request a solution using the "Request Answer" link.
### Physics Problem Description #### Scenario: A 280-kg load is lifted 22.0 meters vertically with an acceleration \(\alpha = 0.140 \, g\) by a single cable. #### Key Variables: - **Mass of load:** 280 kg - **Vertical distance:** 22.0 meters - **Acceleration:** \( \alpha = 0.140 \, g \) Where \( g \) represents the acceleration due to gravity, approximately \( 9.81 \, \text{m/s}^2 \). This problem involves the application of Newton’s laws and principles of mechanics to determine the forces involved in lifting the load. #### Analysis and Calculation: Students may be asked to calculate the tension in the cable or the work done in lifting the load, using formulas such as: - \( F_{\text{net}} = m \cdot (g + \alpha) \) - \( W = F \cdot d \) Where \( F_{\text{net}} \) is the net force, \( m \) is the mass, \( g \) is the acceleration due to gravity, \( \alpha \) is the additional acceleration provided by the cable, \( W \) represents work done, and \( d \) is the displacement. This scenario is useful for understanding the dynamics of forces and motion in physics.
Transcribed Image Text:### Physics Problem Description #### Scenario: A 280-kg load is lifted 22.0 meters vertically with an acceleration \(\alpha = 0.140 \, g\) by a single cable. #### Key Variables: - **Mass of load:** 280 kg - **Vertical distance:** 22.0 meters - **Acceleration:** \( \alpha = 0.140 \, g \) Where \( g \) represents the acceleration due to gravity, approximately \( 9.81 \, \text{m/s}^2 \). This problem involves the application of Newton’s laws and principles of mechanics to determine the forces involved in lifting the load. #### Analysis and Calculation: Students may be asked to calculate the tension in the cable or the work done in lifting the load, using formulas such as: - \( F_{\text{net}} = m \cdot (g + \alpha) \) - \( W = F \cdot d \) Where \( F_{\text{net}} \) is the net force, \( m \) is the mass, \( g \) is the acceleration due to gravity, \( \alpha \) is the additional acceleration provided by the cable, \( W \) represents work done, and \( d \) is the displacement. This scenario is useful for understanding the dynamics of forces and motion in physics.
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