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A particle of mass m = force, whose potential energy function is given by U(x) = x4 – 2x² + 4 (where U is measured in Joules and x is measured in meters). At the moment when the particle is located at position x = 1.50 m, its speed is v = 2.50 m/s. 1.50 kg moves along one dimension and is subject to a single -

A particle of mass m = force, whose potential energy function is given by U(x) = x4 – 2x² + 4 (where U is measured in Joules and x is measured in meters). At the moment when the particle is located at position x = 1.50 m, its speed is v = 2.50 m/s. 1.50 kg moves along one dimension and is subject to a single -

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(a) What is the total mechanical energy of the system? (b) What range of positions is the particle restricted to? (c) What is the speed of the particle when x 1.00 m?
Transcribed Image Text:(a) What is the total mechanical energy of the system? (b) What range of positions is the particle restricted to? (c) What is the speed of the particle when x 1.00 m?
A particle of mass m = 1.50 kg moves along one dimension and is subject to a single force, whose potential energy function is given by U(x) = x4 – 2x2 + 4 (where U is measured in Joules and x is measured in meters). At the moment when the particle is located at position x = 1.50 m, its speed is v = 2.50 m/s. %3D
Transcribed Image Text:A particle of mass m = 1.50 kg moves along one dimension and is subject to a single force, whose potential energy function is given by U(x) = x4 – 2x2 + 4 (where U is measured in Joules and x is measured in meters). At the moment when the particle is located at position x = 1.50 m, its speed is v = 2.50 m/s. %3D
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