A force F(x) = 3.3 2N acts on a particle as it moves along the positive x-axis. (a) How much work (in J) does the force do on the particle as it moves from x = 2.8 m to x = 5.8 m? 1.1 (b) Picking a convenient reference point of the potential energy to be zero at x = 1 m, find the potential energy for this force. (Use the following as necessary: x. Assume U(x) is in joules and x is in meters. Do not include units in your answer.) U(x) =

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Chapter1: Units, Trigonometry. And Vectors
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3.3
A force F(x) =|
N acts on a particle as it moves along the positive x-axis.
(a) How much work (in J) does the force do on the particle as it moves from x = 2.8 m to x = 5.8 m?
1.1
X J
(b) Picking a convenient reference point of the potential energy to be zero at x = 1 m, find the potential energy for this force. (Use the following as necessary: x. Assume U(x) is in joules and x is in
meters. Do not include units in your answer.)
U(x) =
Transcribed Image Text:3.3 A force F(x) =| N acts on a particle as it moves along the positive x-axis. (a) How much work (in J) does the force do on the particle as it moves from x = 2.8 m to x = 5.8 m? 1.1 X J (b) Picking a convenient reference point of the potential energy to be zero at x = 1 m, find the potential energy for this force. (Use the following as necessary: x. Assume U(x) is in joules and x is in meters. Do not include units in your answer.) U(x) =
A particle of mass 4.0 kg moves under the influence of the force F(x) = (-5x2 + 7x) N. If its speed at x = -2.4 m is v = 24.0 m/s, what is its speed (in m/s) at x = 2.4 m?
m/s
Transcribed Image Text:A particle of mass 4.0 kg moves under the influence of the force F(x) = (-5x2 + 7x) N. If its speed at x = -2.4 m is v = 24.0 m/s, what is its speed (in m/s) at x = 2.4 m? m/s
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