A particle of mass m and charge q is re- leased at rest in a uniform field of magnitude E. The uniform field is created between two parallel plates of charge densities to and -o, respectively. The particle accelerates towards the other plate a distance d away. Determine the speed at which it strikes the opposite plate. -ot, y 9 E Origin Fig. ► X
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A: Please post the remaining questions separately!


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- At one point above Earth's surface a uniform electric field points straight up with a magnitude of 53 N/C. A small charged 10.0 mg bead is held stationary 1.0 m above the ground. What is the charge on the bead if it has an initial upward acceleration of 29.4 m/s? when it is released from rest?In the figure the four particles are fixed in place and have charges q₁ = 92 = 4e, 93 = 2e, and 94 = -8e. Distance d = 5.96 µm. What is the magnitude of the net electric field at point P due to the particles? Number i Stop A Units His de lu 91 d P > 93 92 94 AThree identical particles have the same mass m and positive charge Q. They are initial at rest in the corners of an equalateral triangle with sides a. One particle is released, What is the speed of the moving charge when it is a large (aka infinity) distance from the other two?
- 417 q6 A 1.94 10-9 C charge has coordinates x = 0, y = −2.00; a 3.30 10-9 C charge has coordinates x = 3.00, y = 0; and a -4.60 10-9 C charge has coordinates x = 3.00, y = 4.00, where all distances are in cm. Determine magnitude and direction for the electric field at the origin and the instantaneous acceleration of a proton placed at the origin.(a) Determine the magnitude and direction for the electric field at the origin (measure the angle counterclockwise from the positive x-axis).Find magnitude and direction (b) Determine the magnitude and direction for the instantaneous acceleration of a proton placed at the origin (measure the angle counterclockwise from the positive x-axis).Find magnitude and directionA pair of vertical charged conducting plates produces kN a uniform field of 12, directed to the right, between the plates. The separation of the plates is 40mm. An electron is projected from plate A, directly towards plate B, with an initial velocity of 4 Mm. Determine the velocity of the electron as it strikes plate B (in Mm) S $ A E 40 mm - B ME
- Three identical particles have the same mass m and the same positive charge Q. They are initially at rest at the corners of an equilateral triangle with side a when one is released while the other charges are held fixed. What is the speed of the moving charge when it is a large distance from the others?In a typical television or in an older computer picture tube (CRT), the electrons that strike the screen to form an image are accelerated between two charged plates that have a potential difference of 2.5×104 V. The plates are separated by a distance of 1.3 cm. Assuming that there is a uniform electric field between the plates, calculate the strength of the field.A pair of vertical charged conducting plates produces a uniform field of 1.1 Nî, directed to the right, between the plates. The separation of the kN plates is 40mm. An electron is projected from plate A, directly towards plate B, with an initial velocity of 6.38 Mm. Determine the velocity of the electron as it strikes plate B (in S Mm) S A E Vo 40 mm B
- A solid plastic ball has a radius of 6.0 cm and has a charge of +3.o nC ( in nano-Coulombs) that is uniformly distributed throughout its volume. Imagine there is a proton being held 1.5 cm away from the surface of the solid plastic ball, and then the proton is released. The proton will accelerate away from the ball, as we know, due to the repulsive electric force. Assuming the ball doesn't move, how fast is the proton moving when it is 5.5 cm away from the surface of the ball?Object A, which has been charged to +10 nC, is at the origin. Object B, which has been charged to -20 nC, is at (x, y) = (0.0 cm, 2.0 cm). What are the magnitude and direction of the electric force on each object?A ▬ >E h d - As shown in the figure above, a positively charged ball is placed at point A and slides down the slope from rest. The area has a uniform electric field E = 12.9 N/C, pointing to the right. The mass of the ball is m = 9 kg and the charge is q = +2.6 C. When the ball reaches point B, it travels horizontally there after. The height from A to B is h = 37 m and the horizontal distance between A and B is d = 30 m. You can ignore friction and use g = 10 m/s for your calculation. %3D How much is the kinetic energy of the ball when it reaches at B (in the unit of J)? Submit Answer Tries 0/2 If the electric field ist changed to the opposite direction, How much is the kinetic energy of the ball when it reaches at B (in the unit of J) now? Submit Answer Tries 0/2 What is the minimum strength of electric field E that can be used to stop the particle right at Point B? N/C