A particle (mass m, charge q) is moving on a circular orbit (radius R) with angular velocity . = 2π a) Show following relations: mean current I = and magnitude of the magnetic moment || Show following relation between angular momentum and magnetic moment: m = 2m qwR² b) Now consider an electron as the orbiting particle: give the magnetic moment as a function of the so- called Bohr magneton μB-eħ/2me und the angular quantum number (see example 11, 3rd exercise). Find out (e.g. internet) what the magnetic moment caused by the spin of the electron is (and compare the value with point b). → for inspiration see also: University Physics Vol.3, Chapter 8.2 and 8.3

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40.
A particle (mass m, charge q) is moving on a circular orbit (radius R) with angular velocity .
2π
a) Show following relations: mean current 1 = 2 and magnitude of the magnetic moment || =qwR²
Show following relation between angular momentum and magnetic moment: m = l
2m
b) Now consider an electron as the orbiting particle: give the magnetic moment as a function of the so-
called Bohr magneton μB-eħ/2me und the angular quantum number (see example 11, 3rd exercise).
Find out (e.g. internet) what the magnetic moment caused by the spin of the electron is (and compare
the value with point b).
→ for inspiration see also: University Physics Vol.3, Chapter 8.2 and 8.3
Transcribed Image Text:40. A particle (mass m, charge q) is moving on a circular orbit (radius R) with angular velocity . 2π a) Show following relations: mean current 1 = 2 and magnitude of the magnetic moment || =qwR² Show following relation between angular momentum and magnetic moment: m = l 2m b) Now consider an electron as the orbiting particle: give the magnetic moment as a function of the so- called Bohr magneton μB-eħ/2me und the angular quantum number (see example 11, 3rd exercise). Find out (e.g. internet) what the magnetic moment caused by the spin of the electron is (and compare the value with point b). → for inspiration see also: University Physics Vol.3, Chapter 8.2 and 8.3
40b: m = -μB sqrt(l (+1)); m = -e/m.S
Transcribed Image Text:40b: m = -μB sqrt(l (+1)); m = -e/m.S
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