A particle has an initial speed vo. It makes a glancing collision with a second particle of equal mass that is stationary. After the collision the speed of the first particle is v and it has been deflected through an angle 8. The velocity of the second particle makes an angle ß with the initial direction of the first particle. Using the conservation of linear momentum principle in the x- and y-directions, respectively, show that tan ß = v sin 8/(vo - v cos 0) and show that if the collision is elastic, v Vo cos 0 B m Before collision m Vo m m After collision I
A particle has an initial speed vo. It makes a glancing collision with a second particle of equal mass that is stationary. After the collision the speed of the first particle is v and it has been deflected through an angle 8. The velocity of the second particle makes an angle ß with the initial direction of the first particle. Using the conservation of linear momentum principle in the x- and y-directions, respectively, show that tan ß = v sin 8/(vo - v cos 0) and show that if the collision is elastic, v Vo cos 0 B m Before collision m Vo m m After collision I
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Transcribed Image Text:A particle has an initial speed vo. It makes a glancing
collision with a second particle of equal mass that is
stationary. After the collision the speed of the first particle
is v and it has been deflected through an angle 8. The
velocity of the second particle makes an angle ß with the
initial direction of the first particle.
Using the conservation of linear momentum principle in
the x- and y-directions, respectively, show that
tan B = v sin 8/(vo - v cos 0)
and show that if the collision is elastic, v = Vo cos 0
--
B
8
E
Before collision
m
Vo
m
3
After collision
I
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