A particle executes a motion on a circular path with a constant speed of 2 m/s. Using normal-tangential coordinates, what is the magnitude of the normal component of velocity?
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In a uniform cicular motion, the velocity of the particle is always tangential to the circle of motion.
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- letter d onlyYou can use the formula for centripetal acceleration OR You have to calculate the average acceleration directly from the definition, a = delta v / delta t. You have to first get a_x by using the velocity's initial and final x components, do a_y from the y components, and then use the Pythagorean formula to get the magnitude of the acceleration vector.A space vehicle is coasting at a constant velocity of 20.5 m/s in the +y direction relative to a space station. The pilot of the vehicle fires a RCS (reaction control system) thruster, which causes it to accelerate at 0.351 m/s2 in the +x direction. After 33.2 s, the pilot shuts off the RCS thruster. After the RCS thruster is turned off, find (a) the magnitude and (b) the direction of the vehicle's velocity relative to the space station. Express the direction as an angle (in degrees) measured from the +y direction.
- A particle is performing uniform circular motion counterclockwise around the origin of an xy coordinate system. The period of the motion (time for one revolution) is 7 s. At some instant, its position vector is 7 = (2 m)î + (-3 m)§. At that instant, what is the velocity v of the particle in unit vector notation.A space vehicle is coasting at a constant velocity of 17.0 m/s in the +y direction relative to a space station. The pilot of the vehicle fires a RCS (reaction control system) thruster, which causes it to accelerate at 0.291 m/s2 in the +x direction. After 54.3 s, the pilot shuts off the RCS thruster. After the RCS thruster is turned off, find (a) the magnitude and (b) the direction of the vehicle's velocity relative to the space station. Express the direction as an angle (in degrees) measured from the +y direction.A pursue at radius 2.00 m and a wallet at radius 3.00 m travel in uniform circular motion on the floor of a merry-go-round as the ride turns. They are on the same radial line. At one instant, the acceleration of the pursue is (2.00 m/s^2)i + (4.00 m/s^2)j. At the instant and in unit-vector notation, what is the acceleration of the wallet?
- A projectile is launched with an initial velocity 38 m/s and an angle from the horizontal of 45°. The acceleration due to gravity is 9.81 m/s². Assume the projectile is launched from the surface of the Earth. i.e., at y (0) = 0. then the altitude of the projectile as a function of time is: y(t) = gt² + vo sin(0)t Where vo is the initial velocity. What is the maximum altitude achieved by the projectile?A marble slides down on a curved path defined by the parabola y = 0.4x2. When it is at point “A” (xA = 2m; yA = 1.6m), the velocity of the marble v = 8m/s and the tangental acceleration due to gravity is dv / dt = 4ms2. Calculate the normal component and the total magnitude of the accelarion of the mable in that instant.A particle confined to the xy-plane is in uniform circular motion around the origin. The x- and y-coordinates of the particle vary with time as follows: x(t) = r sin(cot) y(t) = r cos(cot). where >= 2.60 m and c = 2.15 s-¹. What are the x- and y-components of the particle's acceleration at an instant when x = 1.00 m and y = 2.40 m. Give your answers by entering numbers into the empty boxes below. ax || || X x² ms ms-2.
- A space vehicle is coasting at a constant velocity of 17.8 m/s in the +y direction relative to a space station. The pilot of the vehicle fires a RCS (reaction control system) thruster, which causes it to accelerate at 0.280 m/s2 in the +x direction. After 33.6 s, the pilot shuts off the RCS thruster. After the RCS thruster is turned off, find (a) the magnitude and (b) the direction of the vehicle's velocity relative to the space station. Express the direction as an angle (in degrees) measured from the +y direction.A particle moves in a circular path at constant speed. The initial location of the particle is (4.24 m, 6.05 m) at t = 4 s. The velocity of the particle at this time is 3.02 m/s 3 (i.e., directed along the positive y-axis). Acceleration at this time is along the +x axis. At t=10.6 s, v is -3.02 m/s i and the acceleration is directed along the +y axis. Find the radius of the circle. For this problem assume the time interval is less than one full period. T Find the x-coordinate of the center of the circle (in meters): Xcenter m = m Question Help: ReadThe position r of a particle moving in an xy plane is given by ř seconds. In unit-vector notation, calculate (a) 7, (b) V , and (c) a for t = 3.00 s. (d) What is the angle between the positive direction of the x axis and a line tangent to the particle's path at t = 3.00 s? Give your answer in the range of (-180°; 180°). (4.00r3 – 1.00t)î + (5.00 – 1.00r4)j with 7 in meters and t in (a) Number i i Units (b) Number ît i Units i (c) Number i i Units (d) Number i Units