A particle can slide along a track with elevated ends and a flat central part, as shown in the figure. The flat part has length L = 44.0 cm. The curved portions of the track are frictionless, but for the flat part the coefficient of kinetic friction is -0.2. The particle is released from rest at point A, which is at height h = L/2. How far from the left edge of the flat part does the particle finally stop? Number i Units A h L
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- You push a 43-kg file cabinet to the right on a frictionless horizontal surface with a force of 225 N from rest, the cabinet moves a distance of 7.3 m. What is the final speed of the cabinet, in m/s? Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.1. Sam, whose mass is 75 kg, takes off across level snow on his jet-powered skis. The skis have a thrust of 200 N and a coefficient of kinetic friction on snow of 0.10. Unfortunately, the skis run out of fuel after only 10 s. A. What is Sam’s top speed? B. How far has Sam traveled when he finally coasts to a stop?An object released from rest slides down a frictionless ramp that makes an angle 0j of 60.0° with the horizontal. The object begins at a height Hj of 12.0 m above the base of the ramp. The bottom end of the ramp merges smoothly with a H second frictionless ramp that rises at angle 02 of 39.0°. H2 What distance d does the object slide along the second ramp before coming to a momentary stop? d = m When the object is on its way back down the second ramp, what is its speed vr at the moment that it is at a height H2 of 7.00 m above the base of the ramp? Uf = m/s
- 13. A block slides along a track with an initial velocity vo = 7.0 m/s from one level to a higher level after passing through an intermediate valley. The difference h from the initial position to the elevated track is 0.89 m. The track is frictionless until reaches the top. What is the velocity of the block when it reaches the top of the track?A golfer hits a shot to a green that is elevated 2.50 m above the point where the ball is struck. The ball leaves the club at a speed of 19.5 m/s at an angle of 40.0° above the horizontal. It rises to its maximum height and then falls down to the green. Ignoring air resistance, find the speed of the ball just before it lands. V = ipervious question: Same type of track as in the previous problem, this time with d = 4.73 m. The block starts at x = 0, and is given a push to the left with an initial speed of 7.57 m/s, so it starts sliding up the track to the left. At what value of x will the block reverse direction and start sliding back down? New question: OK, same sort of track, but now with d = 2.12 m. Now suppose the blocks starts on the track at x = 4.10 m. The block is given a push to the left and begins to slide up the track, eventually reaching its maximum height at x = 0, at which point it turns around and begins sliding down. What was its initial speed in this case? 18.98 m/s 12.47 m/s 8.82 m/s 14.90 m/s
- A student releases a 3.9kg cart from the top of ramp and starts a stopwatch. The length from the front of the cart to the end of the ramp and the distance from the end of the ramp to the stopper are shown. Neglect backwards friction and drag and assume the cart does not lose speed transitioning from the ramp to the floor. What is the cart's acceleration on the ramp? unit | (magnitude) What is the cart's acceleration on the floor? 130cm unit (magnitude) How long does the cart take to reach the end of the ramp? 5° 200cm unit (timed from the release) How fast is the cart traveling as it hits the stopper? unit How long does the cart take to reach the stopper? unit (timed from the release) cannot be detern check answers challenge ne Calculator ound = 343m/s cant figures Rain to stop e here to search ACC t;320A clown is juggling four balls simultaneously. Students use a video tape to determine that it takes the clown 0.9 s to cycle each ball through his hands (including catching, transferring, and throwing) and to be ready to catch the next ball. What is the minimum vertical speed the clown must throw each ball upward with?a 500 N block fromtesfrom rest slides 6m down a 45 degrees slope. the 3m along a level surface and then up 30 degrees incline until it comes to rest again. the coefficient of friction is 0.15 for all surfaces. what is the distance travelled by the block up the 30 degrees inclined yntiuntil it stops. what is the total distance traveled by the block. what is the velocity when uit reach the level surface. what is the velocity of the block just before it travels up the 30 degrees inclined.
- A constant applied force F, of 11.0 N pushes a box with a mass m = coefficient of kinetic friction between the box and the floor is 0.110. 6.00 kg a distance x = 15.0 m across a level floor. The m Assuming that the box starts from rest, what is the final velocity vf of the box at the 15.0 m point? Uf = m/s If there were no friction between the box and the floor, what applied force Fnew Would give the box the same final velocity? Fnew Nm A child stands in the middle of a trampoline and accelerates downward at a rate of 9.8 - 15y where y is the child's positon relative to the unstretched equilibrium position of the trampoline. Assume the child starts from rest at y = 0 and find: A. The maximum downward distance the child travels B. The maximum velocity of the childWnet = m(v₁)² = m(v₁)², Wnet = Σ₁ W₁, W = Fd cos 0 Problem 1: A 2.0 kg box slides on a floor. A friction force of 5.0 N opposes the motion. If the box starts with a speed of 5.5 m/sec, how far does is slide before coming to rest? Answer: d = 6.1 m Problem 2: What is the force a 60.0 kg sprinter exerts backward on the track to accelerate from 2.00 m/sec to 8.00 m/sec in a distance of 25.0 m, if they encounter a wind that exerts an average force of 30.0 N against them? Hint: Wnet = Wrunner - Wwind. Answer: Frunner: = 102.0 N Problem 3: A 500-kg dragster accelerates from rest to a final speed of 110 m/sec in 400 m (about a quarter of a mile) and encounters an average frictional force of 1200 N. What is the work done by the dragster? Hint: Wnet = Wdragster - Wfriction. Answer: Wdragster = 3.5 × 106 J