A parallel plate capacitor with plates of area (A) and plate separation (d) is changed so that the potential difference between its plates is (V). While the capacitor is still connected to the power source and its plate separation is increased to 4d, which statement is correct?

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Chapter1: Units, Trigonometry. And Vectors
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A parallel plate capacitor with plates of area (A) and plate separation (d) is changed so that the potential difference between its plates is (V). While the capacitor is still connected to the power source and its plate separation is increased to 4d, which statement is correct?

The voltage between the plates is unchanged.
The voltage between the plates is decreased to one-half its original value.
The charge on the plates is decreased to one-half its original value.
The capacitance is unchanged.
The capacitance is increased two times its original value.
The charge on the plates is increased two times its original value.
7 x 175he capacitance is decreased to one-half its original value.
Transcribed Image Text:The voltage between the plates is unchanged. The voltage between the plates is decreased to one-half its original value. The charge on the plates is decreased to one-half its original value. The capacitance is unchanged. The capacitance is increased two times its original value. The charge on the plates is increased two times its original value. 7 x 175he capacitance is decreased to one-half its original value.
Expert Solution
Step 1

Given 

Voltage V 

Initial distance between plates d

Final distance 4d

Area A

 

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