A parallel-plate capacitor, with air between the plates, is connected across a voltage source. This source establishes a potential difference between the plates by placing charge of magnitude 2.20 x 10^-6 C. on each plate. The space between the plates is then filled with a dielectric material, with a dielectric constant of 2.22. What must the magnitude of the charge on each capacitor plate now be, to produce the same potential ditterence
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An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
A parallel-plate capacitor, with air between the plates, is connected across a voltage source.
This source establishes a potential difference between the plates by placing charge of
magnitude 2.20 x 10^-6 C. on each plate. The space between the plates is then filled with a
dielectric material, with a dielectric constant of 2.22. What must the magnitude of the charge on
each capacitor plate now be, to produce the same potential ditterence between the plates as
before?
Given ,
Charge on plates of capacitor (q) = 2.20×10-6 C
Dielectric constant of dielectric material is K=2.22
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