A parallel-plate capacitor with plate area of A = 3.0 ×10−2 m2 and plate separation of d = 4.0 mm is connected to a battery which shows V = 50 V , such that the capacitor is fully charged. Now we disconnect the battery and place a dielectric slab of K = 2.2 between both plates, as shown a)Calculate the capacitance C in the presence of the dielectric. b) Briefly explain what happens to the charge Q when the battery is disconnected. c) Briefly explain how the presence of the dielectric affects the electric field, E-> .
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An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
A parallel-plate capacitor with plate area of A = 3.0 ×10−2 m2 and plate separation of d = 4.0 mm
is connected to a battery which shows V = 50 V , such that the capacitor is fully charged. Now
we disconnect the battery and place a dielectric slab of K = 2.2 between both plates, as shown
a)Calculate the capacitance C in the presence of the dielectric.
b) Briefly explain what happens to the charge Q when the battery is disconnected.
c) Briefly explain how the presence of the dielectric affects the electric field, E-> .
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