A parallel plate capacitor used in a flash for a camera must be able to store 32.6 J of energy when connected to 301 V. (Most electronic flashes actually use a 1.50- to 6.00-V battery, but increase the effective voltage using a dc–dc inverter.) Assuming the capacitor completely discharges to produce a flash in 4.20×10−3 s, what average power is dissipated in the flashbulb during this time? (need answer in kW)

Q: Chapter 27, Problem 041 In the figure &₁ = 3.70 V, E2 = 0.987 V, R₁ = 5.78 , R₂ = 2.86 2, R3 = 5.98…

A: As per the guidelines i can solve only first question at a time so please another question…

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