A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 2.90 and whose dielectric strength is 2.20 x 10 V/m. The desired capacitance is 0.100 uf, an capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates 0.39 x Find an expression for the plate separation that at the maximum potential difference just barely leads to dielectric breakdown Use that separation to find the area that would give the desires

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter20: Electric Potential And Capacitance
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A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 2.90 and whose dielectric strength is 2.20 x 10 V/m. The desired capacitance is 0.100 ur, and e
capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates.
0.39
x
Find an expression for the plate separation that at the maximum potential difference just barely leads to dielectric breakdown Use that separation to find the area that would give the desired
capacitance, m
Transcribed Image Text:A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 2.90 and whose dielectric strength is 2.20 x 10 V/m. The desired capacitance is 0.100 ur, and e capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates. 0.39 x Find an expression for the plate separation that at the maximum potential difference just barely leads to dielectric breakdown Use that separation to find the area that would give the desired capacitance, m
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