A parallel-plate capacitor is constructed by filling the space between two square plates with a block of three dielectric materials, as shown in the figure below. You may assume that {» d. (a) Find an expression for the capacitance of the device in terms of the plate area A and d, K1, K2, and K3. (Use the following as necessary: K1, K2, K3, E0, A and d.) C = (b) Calculate the capacitance using the values A = 1.00 cm2, d = 2.00 mm, K1 = 4.90, K2 = 5.60, and K3 = 2.50. F
A parallel-plate capacitor is constructed by filling the space between two square plates with a block of three dielectric materials, as shown in the figure below. You may assume that {» d. (a) Find an expression for the capacitance of the device in terms of the plate area A and d, K1, K2, and K3. (Use the following as necessary: K1, K2, K3, E0, A and d.) C = (b) Calculate the capacitance using the values A = 1.00 cm2, d = 2.00 mm, K1 = 4.90, K2 = 5.60, and K3 = 2.50. F
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Transcribed Image Text:A parallel-plate capacitor is constructed by filling the space between two
square plates with a block of three dielectric materials, as shown in the
figure below. You may assume that { » d.
(a) Find an expression for the capacitance of the device in terms of the
plate area A and d, K1, K2, and K3. (Use the following as necessary: K1,
K2, K3, E0, A and d.)
C =
(b) Calculate the capacitance using the values A = 1.00 cm2, d = 2.00
mm, K1 = 4.90, K2 = 5.60, and K3 = 2.50.
%3D
F
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