A parallel-plate capacitor is constructed by filling the space between two square plates with a block of three dielectric materials, as shown in the figure below. You may assume that { >> d. d/2 (a) Find an expression for the capacitance of the device in terms of the plate area A and d, x₁, K2, and K. (Use the following as necessary: K₁, K2, K3, 80, A and d.) C = (b) Calculate the capacitance using the values A = 1.10 cm2, d = 2.00 mm, k₁ = 4.90, x2 = 5.60, and K3 = 2.40. F

A parallel-plate capacitor is constructed by filling the space between two square plates with a block of three dielectric materials, as shown in the figure below. You may assume that { >> d. d/2 (a) Find an expression for the capacitance of the device in terms of the plate area A and d, x₁, K2, and K. (Use the following as necessary: K₁, K2, K3, 80, A and d.) C = (b) Calculate the capacitance using the values A = 1.10 cm2, d = 2.00 mm, k₁ = 4.90, x2 = 5.60, and K3 = 2.40. F

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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In Lab 3, we measured the dielectric constant of glass using a parallel plate capacitor. Suppose that a piece of flat glass panel with a linear dielectric constant ɛ, = 2.5 is inserted between the plates of such a capacitor. The thickness of the glass is d = 5mm. The glass is in contact with both plates. One of the plates of the capacitor is kept at +3V, and the other plate is grounded. Treat the plates as infinitely large and thus the electric field is uniform between the plates. a) Calculate the electric field between the plates. b) Calculate the (uniform) polarization created in the glass. c) Calculate the surface bound charge density on the side of the glass that is in contact with the positive plate of the capacitor. d) Calculate the electric displacement between the plates. e) Calculate the free charge per unit area on the positive plate of the capacitor.
Solve it correctly please.
I have attached the formulas and values tahat we use for reference. Please include a detailed solution. Thank you!Question:A capacitor consists of two square metal plates, each measuring 8.65x10 ^-3 m on a side. In between, the plates are a sheet of paraffin measuring 2.00x10 ^-5m thick. A. What is the capacitance of this capacitor? (express your answer in pico(p))B. If the charge in one plate is 4.00x10^-9 C. What is the potential difference between the plates?
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I have attached the formulas and values tahat we use for reference. Please include a detailed solution. Thank you!Question:A capacitor consists of two square metal plates, each measuring 8.65x10 ^-3 m on a side. In between, the plates are a sheet of paraffin measuring 2.00x10 ^-5m thick. A. What is the capacitance of this capacitor? (express your answer in pico(p))B. If the charge in one plate is 4.00x10^-9C. What is the potential difference between the plates?
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