A parallel plate capacitor is charged so that the potential difference between the plates is V. Then the battery and wires are disconnected. Using insulated handles, the charged plates are pulled apart to twice the original separation (d to 2d). The Electric Field between the plates now O increases to twice the original values O decreases to half the original value O stays the same O Not enough info to make any of the above statements
A parallel plate capacitor is charged so that the potential difference between the plates is V. Then the battery and wires are disconnected. Using insulated handles, the charged plates are pulled apart to twice the original separation (d to 2d). The Electric Field between the plates now O increases to twice the original values O decreases to half the original value O stays the same O Not enough info to make any of the above statements
Related questions
Question
Transcribed Image Text:**Educational Content: Understanding the Behavior of a Parallel Plate Capacitor**
**Scenario:**
A parallel plate capacitor is initially charged so that the potential difference between the plates is \( V \). After charging, the battery and wires are disconnected. Using insulated handles, the charged plates are pulled apart to double the original separation distance (from \( d \) to \( 2d \)).
**Question:**
What happens to the electric field between the plates now?
**Options:**
- Increases to twice the original value.
- Decreases to half the original value.
- Stays the same.
- Not enough info to make any of the above statements.
*Note: For proper understanding, consider concepts of electric field strength in relation to plate separation and charge maintenance after the disconnection from a power source.*
Expert Solution
Step 1
If d is the distance between plates Q is the charge stores, V is the potential across the capacitor, C is the capacitance, A is the area of plate, is the charge density, and is the permittivity of free space, then electric field E can be written as,
And,
Then,
And in terms of V, an electric field can be written as,
Step by step
Solved in 3 steps
