A paper-filled capacitor is charged to a potential difference of Vo = 2.9 V. The dielectric constant of paper is K = 3.7. Thecapacitor is then disconnected from the charging circuit and the paper filling is withdrawn, allowing air to fill the gap betweenthe plates. Find the new potential difference Vị of the capacitor.Vị =VWhile the capacitor is disconnected from the charging circuit, an unknown substance is inserted between the plates. The platesthen attain a potential difference that is 0.53 times the original potential difference Vo (when paper filled the capacitor). What isthis unknown substance's dielectric constant Ku?Ku =

Given: Initial Volatge,V0=2.9VDielectric Constant,κ=3.7 The dielectric constant is a ratio between a…

A paper-filled capacitor is charged to a potential difference of Vo = 2.9 V. The dielectric constant of paper is K = 3.7. The capacitor is then disconnected from the charging circuit and the paper filling is withdrawn, allowing air to fill the gap between the plates. Find the new potential difference V of the capacitor. Vị = While the capacitor is disconnected from the charging circuit, an unknown substance is inserted between the plates. The plates then attain a potential difference that is 0.53 times the original potential difference V (when paper filled the capacitor). What is this unknown substance's dielectric constant K? Ku =

A paper-filled capacitor is charged to a potential difference of Vo = 2.9 V. The dielectric constant of paper is K = 3.7. The capacitor is then disconnected from the charging circuit and the paper filling is withdrawn, allowing air to fill the gap between the plates. Find the new potential difference V of the capacitor. Vị = While the capacitor is disconnected from the charging circuit, an unknown substance is inserted between the plates. The plates then attain a potential difference that is 0.53 times the original potential difference V (when paper filled the capacitor). What is this unknown substance's dielectric constant K? Ku =