A paper capacitor consists of two aluminum foil plates, each 10 feet long and 1.5 inches wide. The waxed paper separating the two plates has a thickness of 0.04 in. The dielectric constant is assumed to be 2. Determine the capacitance of the capacitor, using both equations

It is given that: l=10 ft=3.048 mw=1.5 in=0.0381 mA=l×w=3.048×0.0381 m2=0.11613 m2d=0.04 in=0.001016…

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Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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A paper capacitor consists of two aluminum foil plates, each 10 feet long and 1.5 inches wide. The waxed paper separating the two plates has a thickness of 0.04 in. The dielectric constant is assumed to be 2. Determine the capacitance of the capacitor, using both equations

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It is given that:

$l = 10 ft = 3.048 m w = 1.5 in = 0.0381 m A = l \times w = 3.048 \times 0.0381 m^{2} = 0.11613 m^{2} d = 0.04 in = 0.001016 m K = 2$

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