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9. What is the result of increasing the frequency of the applied voltage to a capacitor? A. Decreased capacitive reactance. B. Decreased current flow. C. Increased capacitive reactance. D. Increased voltage.

9. What is the result of increasing the frequency of the applied voltage to a capacitor? A. Decreased capacitive reactance. B. Decreased current flow. C. Increased capacitive reactance. D. Increased voltage.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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### Question 9 **What is the result of increasing the frequency of the applied voltage to a capacitor?** A. Decreased capacitive reactance. B. Decreased current flow. C. Increased capacitive reactance. D. Increased voltage. --- This question focuses on the behavior of a capacitor in an AC circuit when the frequency of the applied voltage is increased. Capacitive reactance (\(X_C\)) is inversely proportional to the frequency (\(f\)) of the applied voltage, which means that as the frequency increases, the capacitive reactance decreases. \[ X_C = \frac{1}{2 \pi f C} \] Where: - \(X_C\) is the capacitive reactance - \(f\) is the frequency - \(C\) is the capacitance Understanding this relationship is crucial in the study of AC circuits as capacitors play a significant role in filtering and tuning applications. Increasing the frequency will result in a lower reactance, thus allowing more current to flow through the capacitor. Therefore, the correct answer is: **A. Decreased capacitive reactance.**
Transcribed Image Text:### Question 9 **What is the result of increasing the frequency of the applied voltage to a capacitor?** A. Decreased capacitive reactance. B. Decreased current flow. C. Increased capacitive reactance. D. Increased voltage. --- This question focuses on the behavior of a capacitor in an AC circuit when the frequency of the applied voltage is increased. Capacitive reactance (\(X_C\)) is inversely proportional to the frequency (\(f\)) of the applied voltage, which means that as the frequency increases, the capacitive reactance decreases. \[ X_C = \frac{1}{2 \pi f C} \] Where: - \(X_C\) is the capacitive reactance - \(f\) is the frequency - \(C\) is the capacitance Understanding this relationship is crucial in the study of AC circuits as capacitors play a significant role in filtering and tuning applications. Increasing the frequency will result in a lower reactance, thus allowing more current to flow through the capacitor. Therefore, the correct answer is: **A. Decreased capacitive reactance.**
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