a pallet of bricks is to be suspended by attaching a rope to it and connecting the other end to a couple of heavy crates on the roof of a building, as shown in (Figure 1). The rope pulls horizontally on the lower crate, and the coefficient of static friction between the lower crate and the roof is 0.707. What is the weight of the heaviest pallet of bricks that can be supported this way?

Q: A 171 N sled is pulled up a 32 degree slope at a constant speed by a force of 187 N. What is the…

A:

Q: A 172 N sled is pulled up a 31 degree slope at a constant speed by a force of 156 N. What is the…

A: weight of sled =mg = 172 N angle =  31 degrees force = F = 156 N

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A:

Q: crate is at rest on a level surface. If the coefficient of static friction between the crate and the…

A: Given:- The mass of the object m = 40 kg  the coefficient of static friction between the crate and…

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A: Given data The weight of the uniform rope is given as Wr = 12 N. The weight of the box is given as…

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A:

Q: You push a box (mass 3 kg) so that its initial speed is 2.2 m/s. It slides across a rough floor…

A: KE=Wfriction12mv2=μkmgdd=v22μkg

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A: Given :  Mass of table, M =  100 kg  Mass of box, m = 20 kg  Coefficient of static friction, u = 0.4…

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A:

Q: A wooden box of mass 30 kg slides on a concrete floor. What is the coefficient of friction if the…

A: Mass of box = 30kg Friction force act on body = 180N

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A: Draw a free-body diagram of the system.

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A: SOlution: Given that T = 950 N angle1 = 28.2 degrees angle2 = 33.7 degrees

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A:

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Q: 18.0 kg 27.0 kg 3.50 5.75 m

A:

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A: Note:- Since you have asked multiple question, we will solve the first question for you. If you want…

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A: T1 = 722 N θ1 = 25.2oθ2 = 29.5oLet the mass of beam = m

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A:

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Q: A block of mass 2 kg is kept on the floor. The coefficient of static friction is 0.4. If a force F…

A: Given : m = 2 kg μs = 0.4 Fapp = 2.5 N

Newton's First Law of Motion

If a very smooth ball is rolled down an inclined surface with zero friction, the ball will continue to roll indefinitely for an infinite time, in an attempt to reach to the same height on the opposite hill!