A pair of narrow, parallel slits separated by 0.250 mm is illuminated by the green component from a mercury vapor lamp (A = 546.1 nm). The interference pattern is observed on a screen l.20 m from the plane of the parallel slits. Calculate the distance (a) from the cen- tral maximum to the first bright region on either side of the central maximum and (b) between the first and second dark bands in the interference pattern.

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A: Given:λ=632.6 nmn=1.33m=3d=.0100 mm

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A: Condition for dark fringes

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A: Write the given values of this problem: λ=578 nm or 578×10-9 md=0.0350 mm or 3.5×10-5 mx=3.20 m

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Q: (a) An air wedge is formed between two glass plates separated at one edge by a very fine wire of…

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Q: The double slit with a distance of 0.01cm between the two slits was illuminated with yellow light…

A: Given, d=0.01cm=1.0*10-4mλ=546 nmL=0.2m

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A: Here, mλ=d sinθmθm=sin-1mλd

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A: Given that,Wavelength : λ = 550 nm = 550×10-9 md = 4.50 μm   = 4.50×10-9 mD = 2.0 mm = 6Here we need…

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A: To find-Whether point P on screen at a distance 4.2 mm from centre is bright or dark.Given-D=1…

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Q: The two most prominent wavelengths in the light emitted by a hydrogen discharge lamp are 656 nm…

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Q: Question 4 A duble alit eprinent has a slit eparation distance of 0.06 mm. The first bright fringe…

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Diffraction of light

In physics, the term diffraction is defined as the bending of light around the corners of the obstacle. As a light ray passes by an aperture, it bends around the edges or through slits, it spreads out through a narrow opening. The diffracted light will produce fringes of bright and dark or colored bands which are labeled as a diffraction pattern.