An air wedge 12.0 cm long is used to measure the thickness of a carbon fiber filament. Using green light of 555 nm you observe 11 dark fringes per cm in the interference pattern. How thick is the carbon filament?
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A: Wavelength λ=560nm Slit width w=d=1.1μm For first minimum m=1
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A: λ=650 nm=650×10-6θ=7.90d=50 cm=500 mmwe know thatnλ=dsinθ nλ=dsinθn×650×10-6=500×sin7.90n=105726.57
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Q: double slit experiment using 532 nm light produces an interference pattern with the 1st order maxima…
A: Wavelength of light= 532nm
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Q: A double slit experiment produces 13 bright fringes while being illuminated by light with a…
A: GivenTotal number of bright fringes (N) = 13Wavelength of light (λ) =531 nm =531 × 10-9 m
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A: Given: R=2.5 m2y1=6 mmλ1=500 nmλ2=50 μmλ3=0.5 nm
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Q: A grating is labelled "500 lines per mm". Calculate the position of the first-order maxima when red…
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A: wavelength = 563nmn = 4D = 86.5cm
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A: Given, Diameter = 0.72 mm Wavelength = 2.5 micrometers We need to find, Angle of the dark fringe =?
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Q: The two most prominent wavelengths in the light emitted by a hydrogen discharge lamp are 656 nm(red)…
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A: R=2.50 m The width of the central maximum means that the distance between the two first dark fringes…
Q: A 596-Å-thick layer of ZnS (n = 2.35) is deposited on glass (n = 1.52). Calculate the normal…
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Q: The intensity of the single-slit diffraction pattern at any angle 0 is given by 1 (0) = 1, (sic)². .…
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Q: Using the result of the problem above, calculate thedistance between fringes for 633-nm light…
A: The distance between the fringes is given by the equation
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