A package is released from a helicopter moving directly upward at 15 m/s. The package strikes the ground 16 s later. How high above the ground was the package when it was released? Neglect friction and express your answer in meters.
A package is released from a helicopter moving directly upward at 15 m/s. The package strikes the ground 16 s later. How high above the ground was the package when it was released? Neglect friction and express your answer in meters.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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If use please use g = 9.8 m/s2
![**Problem Statement:**
A package is released from a helicopter moving directly upward at 15 m/s. The package strikes the ground 16 s later.
**Question:**
How high above the ground was the package when it was released?
*Assumptions:*
- Neglect friction and express your answer in meters.
**Instructions:**
Use the laws of motion to calculate the initial height of the package when it was released. Consider using the equation for the motion of objects under gravity:
\[ y = v_i t + \frac{1}{2} a t^2 \]
Where:
- \( y \) is the height from which the package was released,
- \( v_i \) is the initial velocity (15 m/s upward in this case),
- \( t \) is the time taken (16 seconds),
- \( a \) is the acceleration due to gravity (approximately -9.81 m/s², the negative sign indicates the direction is downward).
Feel free to show your work and input the final answer in the space provided below.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F514923f2-e704-4cb3-8e16-d4c01e5e97ad%2Ffc7f893f-75d4-4c54-8d55-d65c5ceae36b%2Fiem5dt4_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A package is released from a helicopter moving directly upward at 15 m/s. The package strikes the ground 16 s later.
**Question:**
How high above the ground was the package when it was released?
*Assumptions:*
- Neglect friction and express your answer in meters.
**Instructions:**
Use the laws of motion to calculate the initial height of the package when it was released. Consider using the equation for the motion of objects under gravity:
\[ y = v_i t + \frac{1}{2} a t^2 \]
Where:
- \( y \) is the height from which the package was released,
- \( v_i \) is the initial velocity (15 m/s upward in this case),
- \( t \) is the time taken (16 seconds),
- \( a \) is the acceleration due to gravity (approximately -9.81 m/s², the negative sign indicates the direction is downward).
Feel free to show your work and input the final answer in the space provided below.
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