A o Zeq в о- 1 Ω ww -j2 n 20 (a) 4 Ω j6n :-j2 0 O a. Zeq = 3,8 + j0,6 0 O b. Zeq = -3,8 + j0,6 O c. Zeq = 3,8-j0,6 O d. Zeq = -3,8 - j0,6 O e. None of the alternatives are correct j20 jan -j20 +

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
A o
Lea
Βο
1 Ω
ww
-jΖΩ
ΖΩ
} j6 Ω
(a)
4 Ω
-j20
a.
Zeq = 3,8 + j0,6 Ω
O b.
Zeq = -3,8 + j0,6 Ω
Ο c.
Zeq = 3,8 - j0,6 Ω
Ο d.
Zeq = -3,8 - j0,6 Ω
O e. None of the alternatives are correct
j2 Ω
j4ΩΣ
-j2 Ω
Transcribed Image Text:A o Lea Βο 1 Ω ww -jΖΩ ΖΩ } j6 Ω (a) 4 Ω -j20 a. Zeq = 3,8 + j0,6 Ω O b. Zeq = -3,8 + j0,6 Ω Ο c. Zeq = 3,8 - j0,6 Ω Ο d. Zeq = -3,8 - j0,6 Ω O e. None of the alternatives are correct j2 Ω j4ΩΣ -j2 Ω
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