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A o Zeq- во- 102 -j20 (a) 40 ww 20 je n -j20 O a. Zeq = 3,8 + j0,6 2 O b. Zeq -3,8 +0,6 O c. Zeq = 3,8-j0,6 O d. Zeq = -3,8-j0,6 O e. None of the alternatives are correct j20 jan -j20

A o Zeq- во- 102 -j20 (a) 40 ww 20 je n -j20 O a. Zeq = 3,8 + j0,6 2 O b. Zeq -3,8 +0,6 O c. Zeq = 3,8-j0,6 O d. Zeq = -3,8-j0,6 O e. None of the alternatives are correct j20 jan -j20

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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A o Lea Βο 1 Ω ww -jΖΩ ΖΩ } j6 Ω (a) 4 Ω -j20 a. Zeq = 3,8 + j0,6 Ω O b. Zeq = -3,8 + j0,6 Ω Ο c. Zeq = 3,8 - j0,6 Ω Ο d. Zeq = -3,8 - j0,6 Ω O e. None of the alternatives are correct j2 Ω j4ΩΣ -j2 Ω
Transcribed Image Text:A o Lea Βο 1 Ω ww -jΖΩ ΖΩ } j6 Ω (a) 4 Ω -j20 a. Zeq = 3,8 + j0,6 Ω O b. Zeq = -3,8 + j0,6 Ω Ο c. Zeq = 3,8 - j0,6 Ω Ο d. Zeq = -3,8 - j0,6 Ω O e. None of the alternatives are correct j2 Ω j4ΩΣ -j2 Ω
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