A numerical example may help to illustrate the geometry involved in Stokes' theorem. Consider the portion of a sphere shown in Figure 7.17. The surface is specified by r = 4,0 ≤ 0 ≤ 0.1, 0≤ ≤ 0.37, and the closed path forming its perimeter is com- posed of three circular arcs. We are given the field H = 6r sin pa, +18r sin 0 cos pa and are asked to evaluate each side of Stokes' theorem. 0.17 r=4₁ 1 1 (2) 0.3л 3
A numerical example may help to illustrate the geometry involved in Stokes' theorem. Consider the portion of a sphere shown in Figure 7.17. The surface is specified by r = 4,0 ≤ 0 ≤ 0.1, 0≤ ≤ 0.37, and the closed path forming its perimeter is com- posed of three circular arcs. We are given the field H = 6r sin pa, +18r sin 0 cos pa and are asked to evaluate each side of Stokes' theorem. 0.17 r=4₁ 1 1 (2) 0.3л 3
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Transcribed Image Text:A numerical example may help to illustrate the geometry involved in Stokes' theorem.
Consider the portion of a sphere shown in Figure 7.17. The surface is specified by r =
4,0 ≤ 0 ≤ 0.1, 0≤ ≤ 0.37, and the closed path forming its perimeter is com-
posed of three circular arcs. We are given the field H = 6r sin pa, +18r sin 0 cos pa
and are asked to evaluate each side of Stokes' theorem.
0.1л
r=4₁
(1)
1
3
(2)
0.3л
Figure 7.17 A portion of a spherical cap is
used as a surface and a closed path to illustrate
Stokes' theorem.
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