A null and alternative hypothesis are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed. Ho: p 2 0.3 H₂: p < 0.3 What type of test is being conducted in this problem? O A. Right-tailed test B. Left-tailed test OC. Two-tailed test
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- Test the claim that the mean GPA of night students is significantly different than the mean GPA of day students at the 0.02 significance level. The null and alternative hypothesis would be: Ho: HN = HD Họ:µN = µD Ho:µN = HD HA:HN + HD HẠ:HN µD The test is: left-tailed right-tailed two-tailed The sample consisted of 30 night students, with a sample mean GPA of 2.68 and a standard deviation of 0.3, and 40 day students, with a sample mean GPA of 2.61 and a standard deviation of 0.2. The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals)two productionUse technology to find the P-value for the hypothesis test described below. The claim is that for a smartphone carrier's data speeds at airports, the mean is μ=16.00 Mbps. The sample size is n=19 and the test statistic is t=1.224.
- first picture is the background informationreview(31a) MAKE SURE YOU SELECT TWO ANSWERS FOR THIS QUESTION.. Type of test and hypotheses. Professor dill wonders if male and female earn significantlly differnent grades, when taking the same course with the same instructor. He randomly samples 160 males. and 100 females. The males receive 20 A's, 32 B's 70 C's 30 D's, anf 8 F's.The female receive 20'A's, 28 B's, 30 C's, and 10 D's. and 12 F's; His hypotheses is that gender and grades are related. Choose the type of test you should choose to test the hypotheses in symbol notation( or in words if symbol is not appropriate) (a) Z test (b)single sample t test (c)dependent t test (d) independent t test (e) Pearson correlation coeffieient. (f) ANOVA (g) chi Square goodness of fit test (h)Chi Square test of independence (i) Ho: u1-u2=0 H1: u1-u2!=0 (j) Ho: u1-u2 =0 H1:u1-u2<0 (k) Ho: u1-u2 >= 0 H1: u1=u2<0 (l) Ho : Rho=0 H1: Rho!=0 (m) Ho: Rho >= 0 H1: Rho <0 (n) Ho:Rho <= 0 H1: Rho >…Test the claim that the proportion of people who own cats is significantly different than 50% at the 0.02 significance level. Based on a sample of 100 people, 48% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
- Decide whether you would reject or fail to reject the null hypothesis in the following situations: = 3.50, sD = 1.10, n = 12, a = .05, two-tailed test 95% CI = (0.20, 1.85) t = 2.98, t* = −2.36, one-tailed test to the left 90% CI = (−1.12, 4.36)If your null and alternative hypothesis are: Ho:p = 0.49 H1:p + 0.49 Then the test is: O left tailed right tailed two tailedst 3 4 25 26 27 28 on 29 K Test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, and then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Among 2073 passenger cars in a particular region, 222 had only rear license plates. Among 339 commercial trucks, 51 had only rear license plates. A reasonable hypothesis is that commercial trucks owners violate laws requiring front license plates at a higher rate than owners of passenger cars. Use a 0.10 significance level to test that hypothesis. a. Test the claim using a hypothesis test. b. Test the claim by constructing an appropriate confidence interval. a. Identify the null and alternative hypotheses for this test. Let population 1 correspond to the passenger cars and population 2 correspond to the commercial trucks. Let a success be a vehicle that only has a rear license plate. O A. Ho: P₁ = P2 H₁: P₁ P2 OB. Ho: P₁ P2 H₁: P₁ P2 OC.…
- Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is u < 98.6 degrees F. The sample size is n=8 and the test statistic is t= negative 1.228. P-value = ____ (Round to three decimal places as needed.)Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is p< 98.6°F. The sample size is n = 7 and the test statistic is t= - 1.321. P-value = (Round to three decimal places as needed.) Enter your answer in the answer box. 00 20 F3 esc F6 F7 F8 F9 F10 F1 F2 F4 F5 & 9. %24The average final exam score for the statistics course is 78%. A professor wants to see if the average final exam score for students who are given colored pens on the first day of class is higher. The final exam scores for the 13 randomly selected students who were given the colored pens are shown below. Assume that the distribution of the population is normal. 90, 84, 93, 77, 95, 79, 82, 70, 85, 70, 83, 100, 90 What can be concluded at the the a = 0.05 level of significance level of significance?