A nucleus with 19 protons travels at a velocity of 9.82 x 10^6 m/s through a region of uniform magnetic field strength 2.66 T. The nucleus experiences a magnetic force of 5.88E-11 N. What angle does the nucleus s velocity vector make with respect to the magnetic field direction? 23.9 degrees 38.2 degrees 71.7 degrees 47.8 degrees

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Chapter1: Units, Trigonometry. And Vectors
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A nucleus with 19 protons travels at a velocity of 9.82 x 10^6 m/s through a region of uniform magnetic field strength 2.66 T. The nucleus experiences a magnetic force of 5.88E-11 N. What angle does the nucleus s velocity vector make with respect to the magnetic field direction?
 

 

 
23.9 degrees
 
38.2 degrees
 
71.7 degrees
 
47.8 degrees
Expert Solution
Step 1: Given information

N u c l e u s space c o n t a i n s space 19 space p r o t o n s. space
space T h e r e f o r e space c h a r g e space o f space n u c l e u s space i s space q space equals space left parenthesis plus 19 e right parenthesis space equals space 19 e space space
w h e r e space e equals 1.6 cross times 10 to the power of negative 19 end exponent C o u l o m b s comma space r e p r e s e n t s space m a g n i t u d e space o f space c h a r g e space o f space o n e space p r o t o n. space
space S o space q space equals space 19 cross times 1.6 cross times 10 to the power of negative 19 end exponent space C o u l o m b s
V e l o c i t y space o f space t h e space g i v e n space n u c l e u s space i s space v equals 9.82 cross times 10 to the power of 6 space m divided by s.
M a g n e t i c space f i e l d space B space equals 2.66 T
T h e space n u c l e u s space e x p e r i e n c e space a space m a g n e t i c space f o r c e space o f space F equals space 5.88 cross times 10 to the power of negative 11 end exponent space N.
 

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