A normally distributed population has mean 1,200and standard deviation 120. Find the probability that the mean of a sample of size 25 drawn from this population is between 1,100 and 1,300. Ans. is Blank 4
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- Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P15, the 15th percentile. This is the bone density score separating the bottom 15% from the top 85%. How to get and what is the bone density score corresponding to P15 is ?2. Approximately 34% of the area under the normal curve of a normal distribution with a mean of 50 falls in the interval (50,62). Find its standard deviation.A standardized exam’s score are normally distributed. In a recent year, the mean test score was 1477 and the standard was 315. The test scores of four students selected at random 1860 1230, 2160, and 1360. Find the Z- score that correspond to each value and determine wether any of the values are unusual. The Z-score for 1860 is-The Z-score for 1230 is-The Z-score for 2160 is-The Z-score for 1360is-
- The mean wage per hour for all 4000 employees working at a large company is RM 10.50 with a standard deviation of RM 5.30. Let x be the mean wage per hour for a random sample of certain employees selected from this company.Answer number 3 only pls.For a group of 200 candidates, the mean and standard deviation of scores were founds to be 40 and 15 respectively. Later on it was discovered that the score 43 and 35 were misread as 34 and 53 respectively. Find the corrected mean and standard deviation corresponding to the correct figures. 1
- In a class with 50 students, a 60-item test is conducted. After the test, it is found that the mean of the scores is 40 and the standard deviation is 5. Assuming normal frequency distribution, determine the scores of the students within 1 standard deviation.Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P87, the 87-percentile. This is the temperature reading separating the bottom 87% from the top 13%.P87 = °CThe salaries of professional baseball players are heavily skewed right with a mean of $3.2 million and a standard deviation of $2 million. The salaries of professional football players are also heavily skewed right with a mean of $1.9 million and a standard deviation of $1.5 million. A random sample of 40 baseball players' salaries and 35 football players' salaries is selected. The mean salary is determined for both samples. Let -T, represent the difference in the mean salaries for baseball and football players. Which of the following represents the standard deviation of the sampling distribution for - -- ? O 0.41 million O 0,57 million Save and Exit Next Submit Mark this and return hp & 4 6. 7 8. 9. y h k
