A non-ionizing organic compound has an emprical formula CH,O. A 1.13 g sample of this compound was dissolved in 34.9 g of a solventwhose Ke value is 8 °C kg mol 1. The freezing point of the solvent depressed by 1.72 °C. Calculate the molecular formula of the organiccompound.a. CGH1206Ob. C3H6O3O c. CSH10O5O d. C,H1407O e. CAH&O4

depression in freezing point ∆Tf = Kf * w2*1000 / M2*w1 Given Weight of the solute = w2 = 1.13g…

A non-ionizing organic compound has an emprical formula CH20. A 1.13 g sample of this compound was dissolved in 34.9 g of a solvent whose Kę value is 8 °C kg mol1. The freezing point of the solvent depressed by 1.72 °C. Calculate the molecular formula of the organic compound. O a. CH12O6 O b. C3H6O3 O c. CSH10O5 O d. C,H1407 O e. CaHgO4

A non-ionizing organic compound has an emprical formula CH20. A 1.13 g sample of this compound was dissolved in 34.9 g of a solvent whose Kę value is 8 °C kg mol1. The freezing point of the solvent depressed by 1.72 °C. Calculate the molecular formula of the organic compound. O a. CH12O6 O b. C3H6O3 O c. CSH10O5 O d. C,H1407 O e. CaHgO4

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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