A new type of force was discovered by physicists with the following expression: a Fnew ,=+ Be* + 3x where alpha & beta are constants, and x is the position. The expression above was obtained from the interaction of a massless Higgs Boson (a type of particle) and a black hole. Quantum physicists then decides to design and build a machine that is able to move the Higgs Boson from x2 to x1. How much work should the machine do to achieve this feat? (For simplicity, consider that no energy is lost in the process) Solution To determine the work done we apply the following W = dx Evaluating the above, we get for the limits from xị to xf substituting x1 and x2 as the limits, the work done is expressed as W = | + B X1 ( x15 - x25 )
anwer according to the blanks:
A new type of force was discovered by physicists with the following expression:
where alpha & beta are constants, and x is the position. The expression above was obtained from the interaction of a massless Higgs Boson (a type of particle) and a black hole.
Quantum physicists then decides to design and build a machine that is able to move the Higgs Boson from x2 to x1. How much work should the machine do to achieve this feat? (For simplicity, consider that no energy is lost in the process)
Solution
To determine the work done we apply the following
W = Blank 1dx
Evaluating the above, we get
W = Blank 2| Blank 3 | + Blank 4eBlank 5 + Blank 6xBlank 7 for the limits from xi to xf
substituting x1 and x2 as the limits, the work done is expressed as
W = Blank 8| Blank 9/Blank 10 | + ( Blank 11x1 - Blank 12 ) + Blank 13( x15 - x25 )
![Problem
A new type of force was discovered by physicists with the following expression:
a
Fnew
+ Bex + 3x4
where alpha & beta are constants, and x is the position. The expression above was obtained from the interaction of a massless Higgs Boson (a type of
particle) and a black hole.
Quantum physicists then decides to design and build a machine that is able to move the Higgs Boson from x2 to x1. How much work should the machine
do to achieve this feat? (For simplicity, consider that no energy is lost in the process)
Solution
To determine the work done we apply the following
Xf
W =
dx
Evaluating the above, we get
W =
e
X
for the limits from xj to xf
substituting x1 and x2 as the limits, the work done is expressed as
W =
| + B
х1
( x15
x25 )](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F32641910-4722-477c-9f2a-23fd0bce9a6b%2Fc6cac75c-240f-4dd0-a028-6ec21579abf3%2Fdlkxph_processed.jpeg&w=3840&q=75)
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