**Problem Statement:**A 10 kg block is pushed with a constant external force of 10 Newtons horizontally on a floor with a kinetic friction coefficient equal to 0.1.**Important:** The acceleration due to gravity, in this problem, has a magnitude of 10 m/s².While the block is pushed over a distance of 9 meters:a. What is the work done by the pushing force?b. What is the work done by the normal force on the block?c. What is the work done by the frictional force on the block?d. What is the total amount of work done on the block?---**Guidance for Solutions:**1. **Work Done by the Pushing Force:** Formula: Work = Force × Distance × cos(θ) Since the force is applied horizontally and the block moves horizontally, θ = 0 degrees, which means cos(0) = 1.2. **Work Done by the Normal Force:** Consider that the normal force acts perpendicular to the displacement of the block. Hence, θ = 90 degrees. Since cos(90) = 0, the work done is zero.3. **Work Done by the Frictional Force:** Calculate the frictional force using: Frictional Force = Coefficient of Friction × Normal Force. The normal force is equal to the weight of the block, which is mass × gravity.4. **Total Work Done on the Block:** Sum the work done by all forces.

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A 10 kg block is pushed with a constant external force of 10 Newtons horizontally on a floor with a kinetic friction coefficient equal to 0.1 Important: The acceleration due to gravity, in this problem, has a magnitude of 10m/s? While the block is pushed over a distance of 9 meters, What je the work done by the puehing force?

A 10 kg block is pushed with a constant external force of 10 Newtons horizontally on a floor with a kinetic friction coefficient equal to 0.1 Important: The acceleration due to gravity, in this problem, has a magnitude of 10m/s? While the block is pushed over a distance of 9 meters, What je the work done by the puehing force?

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Chapter1: Units, Trigonometry. And Vectors

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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

**Problem Statement:**

A 10 kg block is pushed with a constant external force of 10 Newtons horizontally on a floor with a kinetic friction coefficient equal to 0.1.

**Important:** The acceleration due to gravity, in this problem, has a magnitude of 10 m/s².

While the block is pushed over a distance of 9 meters:

a. What is the work done by the pushing force?

b. What is the work done by the normal force on the block?

c. What is the work done by the frictional force on the block?

d. What is the total amount of work done on the block?

---

**Guidance for Solutions:**

1. **Work Done by the Pushing Force:**

Formula: Work = Force × Distance × cos(θ)

Since the force is applied horizontally and the block moves horizontally, θ = 0 degrees, which means cos(0) = 1.

2. **Work Done by the Normal Force:**

Consider that the normal force acts perpendicular to the displacement of the block. Hence, θ = 90 degrees. Since cos(90) = 0, the work done is zero.

3. **Work Done by the Frictional Force:**

Calculate the frictional force using: Frictional Force = Coefficient of Friction × Normal Force.

The normal force is equal to the weight of the block, which is mass × gravity.

4. **Total Work Done on the Block:**

Sum the work done by all forces.

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