A new automated production process averages 1.8 breakdowns per day. Because of the cost associated with a breakdown, management is concerned about the possibility of having three or more breakdowns during a day. Assume that breakdowns occur randomly, that the probability of a breakdown is the same for any two time intervals of equal length, and that breakdowns in one period are independent of breakdowns in other periods. What is the probability of having three or more breakdowns during a day? Step 1 It is given that the probability of a breakdown is the same for time intervals of equal length and that breakdowns are independent of one another. These are the necessary properties for a Poisson experiment. Recall the formula for calculating the probability f(x) of x occurrences in a time interval when there is an average of μ occurrences in time intervals of the same length. f(x) =  μxe−μ x! There is an average of 1.8 breakdowns per day and of concern is having three or more breakdowns per day. Therefore,  μ =  .

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QUESTION 15

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A new automated production process averages 1.8 breakdowns per day. Because of the cost associated with a breakdown, management is concerned about the possibility of having three or more breakdowns during a day. Assume that breakdowns occur randomly, that the probability of a breakdown is the same for any two time intervals of equal length, and that breakdowns in one period are independent of breakdowns in other periods. What is the probability of having three or more breakdowns during a day?
Step 1
It is given that the probability of a breakdown is the same for time intervals of equal length and that breakdowns are independent of one another. These are the necessary properties for a Poisson experiment.
Recall the formula for calculating the probability f(x) of x occurrences in a time interval when there is an average of μ occurrences in time intervals of the same length.
f(x) = 
μxe−μ
x!
There is an average of 1.8 breakdowns per day and of concern is having three or more breakdowns per day. Therefore, 
μ =  .
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