A net force of 9.0 N acts through a distance of 3.0 m in a time of 3.0 s. The work done is

College Physics
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Here is a transcription of the text from the image, formatted appropriately for an educational website:

---

**Data Points:**

- **a:** 3.0 J
- **b:** 9.0 J
- **c:** 27 J
- **d:** 81 J

---

In the above list, "a," "b," "c," and "d" represent distinct variables or conditions, and the associated numerical values (3.0 J, 9.0 J, 27 J, and 81 J) indicate their respective energy measurements in joules (J). This information can be used for various educational purposes, such as demonstrating energy conversion, understanding proportional relationships, or solving physics-related problems.

The numerical values are likely increasing exponentially, which is a pattern often seen in exponential growth or decay scenarios.

No graphs or diagrams are provided in the image.

---
Transcribed Image Text:Here is a transcription of the text from the image, formatted appropriately for an educational website: --- **Data Points:** - **a:** 3.0 J - **b:** 9.0 J - **c:** 27 J - **d:** 81 J --- In the above list, "a," "b," "c," and "d" represent distinct variables or conditions, and the associated numerical values (3.0 J, 9.0 J, 27 J, and 81 J) indicate their respective energy measurements in joules (J). This information can be used for various educational purposes, such as demonstrating energy conversion, understanding proportional relationships, or solving physics-related problems. The numerical values are likely increasing exponentially, which is a pattern often seen in exponential growth or decay scenarios. No graphs or diagrams are provided in the image. ---
### Physics Problem: Calculating Work Done

**Problem Statement:**
A net force of 9.0 N acts through a distance of 3.0 m in a time of 3.0 s. The work done is

**Explanation:**
To find the work done (W), we can use the formula:

\[ W = F \times d \]

where
- \( F \) is the force applied (in newtons, N)
- \( d \) is the distance over which the force is applied (in meters, m)

Given:
- \( F = 9.0 \) N
- \( d = 3.0 \) m

Substituting the values into the formula:

\[ W = 9.0 \, \text{N} \times 3.0 \, \text{m} \]

\[ W = 27.0 \, \text{J} \]

**Answer:**
The work done is 27.0 joules (J).
Transcribed Image Text:### Physics Problem: Calculating Work Done **Problem Statement:** A net force of 9.0 N acts through a distance of 3.0 m in a time of 3.0 s. The work done is **Explanation:** To find the work done (W), we can use the formula: \[ W = F \times d \] where - \( F \) is the force applied (in newtons, N) - \( d \) is the distance over which the force is applied (in meters, m) Given: - \( F = 9.0 \) N - \( d = 3.0 \) m Substituting the values into the formula: \[ W = 9.0 \, \text{N} \times 3.0 \, \text{m} \] \[ W = 27.0 \, \text{J} \] **Answer:** The work done is 27.0 joules (J).
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