### Statistical Analysis of Air Traffic Control DataA national air traffic control system reported managing an average of 47,732 flights over a sample of 28 randomly chosen days in a particular year. The standard deviation for this sample was calculated to be 6,343 flights per day. Below are the steps to complete the statistical analysis:#### Task:a. Construct a 99% confidence interval to estimate the average number of flights per day handled by the system.#### Solution:To construct the 99% confidence interval, the calculations for the lower and upper limits need to be completed.- **Confidence Interval:** - **Lower limit:** [Insert lower limit here] - **Upper limit:** [Insert upper limit here]**Note:** Values should be rounded to the nearest whole numbers.This analysis helps to understand the range within which the true average number of flights per day handled by the air traffic control system is expected to fall, with a 99% confidence level.

Suppose µ is the population average number of flights per day handled by the system.

Answered: A national air traffic control system…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Exercise 1.4 (5pts). A farmer recorded the weights of 25 randomly selected pigs from his farm. A 95% confidence interval for the mean weight was calculated to be from 280.2 to 289.8 pounds. What is being estimated by this confidence interval? Choose one: a. the weights of all pigs at this farm. b. the mean weight of 25 pigs at this farm. c. the mean weight of all pigs at this farm. d. the middle 95% of weights for pigs at this farm.
Calculate the 95% confidence interval and the 99% confidence interval for a sample of 81 where the population has a mean of 50 and a standard deviation of 6.
You measure 34 turtles' weights, and find they have a mean weight of 65 ounces. Assume the population standard deviation is 5.2 ounces. Based on this, what is the maximal margin of error associated with a 95% confidence interval for the true population mean turtle weight.
MODULE 2 2. A sample of 20 bags of the same brand of candies was selected and found a mean weight of 120 grams. Assume that the population distribution of bag weights is normal. The weight of each bag was then recorded. The population standard deviation is known to be 2.1 grams. Construct a 90% confidence interval for the population mean weight of the candies. 3. A survey of 200 Internet users shows that they spend an average of 2 hours and 22 minutes per day on social networking. If the margin of error is 2.2 hours at 95% confidence, construct the confidence interval. 4. Suppose that a government law office does a study to determine the time needed to complete one personal profile sheet for consultation. It randomly surveys 100 people. The sample mean is 23.6 minutes. There is a known standard deviation of 7.0 minutes. The population distribution is assumed to be normal. Construct a 95% confidence interval for the population mean to complete the form. 5. A camp counselor is interested…
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
You measure 43 watermelons' weights, and find they have a mean weight of 72 ounces. Assume the population standard deviation is 14.4 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean watermelon weight.Give your answer as a decimal, to two places
Exercise 3. A personal manager has found that historically the scores on aptitude tests given to applicants for entry-level positions follow a normal distribution with a standard deviation of 32.4 points. A random sample of nine test scores from the current group of applicants had a mean score of 187.9 points. a. Find an 80% confidence interval for the population mean score of the current group of applicants. b. Based on these sample results a statistician found for the population mean a confidence interval extending from 165.8 to 210.0 points. Find the confidence level of this interval.
The following data represent a random sample of five measurements from a normally distributed population: 7,4,2,5,7 a. Find 90% confidence interval for u. b. Find a 99% confidence interval for u.
Assume that the 95% confidence interval for mean=9 and standard devaition=20. For a particular data, the standardized value z = 2.73. We can say that: Select one: a. The data with standardized value 2.73 does not belong to the confidence interval and the value is less than the average. b. The data with standardized value 2.73 does not belong to the confidence interval and the value is greater than the average. c. Cannot interpret the z-value information provided. d. The data with standardized value 2.73 if it belongs to the confidence interval and the value is less than the average. e. The data with standardized value 2.73 if it belongs to the confidence interval and the value is greater than the average.
Which type of confidence interval should you use in this situation? A sample of 25 different payroll departments found that the employees worked an average of 310.3 days a year with a standard deviation of 23.8 days. The distribution is approximately normally distributed. Find the 90% confidence interval for the average days worked of all payroll departments. Question 2 options: 1) a confidence interval for the mean using a table value from the standard normal distribution. 2) a confidence interval for the mean using a table value from the t distribution. 3) a confidence interval for a proportion using a table value from the standard normal distribution. 4) a confidence interval for proportion using a table value from the t distribution. 5) none of the above.
A student records the repair cost for 17 randomly selected TVs. A sample mean of $73.10 and standard deviation of $16.01 are subsequently computed. Determine the 90% confidence interval for the mean repair cost for the TVs. Assume the population is approximately normal. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.

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