A narrow beam of yellow light (do = 590 nm) is incident from air on a smooth surface of water at an angle of 8, = 45.0°. Determine the angle of refraction, 02, and the wavelength of the light in water. • (angle of refraction) nm (wavelength in water)

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### Refraction of Yellow Light in Water

**Problem Statement:**
A narrow beam of yellow light (λ₀ = 590 nm) is incident from air on a smooth surface of water at an angle of θ₁ = 45.0°. Determine the angle of refraction, θ₂, and the wavelength of the light in water.

**Required to Determine:**
1. Angle of refraction (θ₂)
2. Wavelength in water (λ)

**Inputs:**
- Incident wavelength in air (λ₀): 590 nm
- Incident angle (θ₁): 45.0°

**Output Boxes:**
- Angle of refraction (θ₂)
- Wavelength in water (λ)

This problem involves applying Snell's Law to determine the angle at which light refracts when it passes from air into water and also requires using the relationship between wavelength and refractive index to find the wavelength of light in water.

### Explanation:

1. **Angle of Refraction (θ₂):**
   To find the angle of refraction, we will use Snell's Law:
   \[
   n_1 \sin(\theta_1) = n_2 \sin(\theta_2)
   \]
   where \( n_1 \) is the refractive index of air (approximately 1), and \( n_2 \) is the refractive index of water (approximately 1.33).

2. **Wavelength in Water (λ):**
   The wavelength of light in water can be found using the relationship:
   \[
   \lambda_2 = \frac{\lambda_1}{n_2}
   \]
   where \( \lambda_1 \) is the wavelength of light in air (590 nm) and \( n_2 \) is the refractive index of water (1.33).

### Visualization:
This problem does not include any graphs or diagrams, but understanding the interaction of light at the boundary between two mediums (air and water) is crucial.

Please input the values into the provided textboxes to determine the correct angle of refraction and wavelength of light in water.
Transcribed Image Text:### Refraction of Yellow Light in Water **Problem Statement:** A narrow beam of yellow light (λ₀ = 590 nm) is incident from air on a smooth surface of water at an angle of θ₁ = 45.0°. Determine the angle of refraction, θ₂, and the wavelength of the light in water. **Required to Determine:** 1. Angle of refraction (θ₂) 2. Wavelength in water (λ) **Inputs:** - Incident wavelength in air (λ₀): 590 nm - Incident angle (θ₁): 45.0° **Output Boxes:** - Angle of refraction (θ₂) - Wavelength in water (λ) This problem involves applying Snell's Law to determine the angle at which light refracts when it passes from air into water and also requires using the relationship between wavelength and refractive index to find the wavelength of light in water. ### Explanation: 1. **Angle of Refraction (θ₂):** To find the angle of refraction, we will use Snell's Law: \[ n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \] where \( n_1 \) is the refractive index of air (approximately 1), and \( n_2 \) is the refractive index of water (approximately 1.33). 2. **Wavelength in Water (λ):** The wavelength of light in water can be found using the relationship: \[ \lambda_2 = \frac{\lambda_1}{n_2} \] where \( \lambda_1 \) is the wavelength of light in air (590 nm) and \( n_2 \) is the refractive index of water (1.33). ### Visualization: This problem does not include any graphs or diagrams, but understanding the interaction of light at the boundary between two mediums (air and water) is crucial. Please input the values into the provided textboxes to determine the correct angle of refraction and wavelength of light in water.
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