A mysterious object is accelerated in a straight line across a table by a mysterious force. The force is not constant, but 100 varies depending on the position of the object. The graph and equations give the magnitude of the force F on the 80 object as a function of the position x of the object. 20 N x + 60 N 2 mm 0 mm < x < 2 mm 60 60 N F (x) = { 110N– 2 mm < x < 6 mm 40 4 mm 40 N -x – 40 N 4 mm 6 mm < x < 10 mm 20 2 4 8 10 Find the work W, done by the force on the object as it x (mm) travels from x = 2.00 mm to x = 9.00 mm. W. = J F(x) (N)
A mysterious object is accelerated in a straight line across a table by a mysterious force. The force is not constant, but 100 varies depending on the position of the object. The graph and equations give the magnitude of the force F on the 80 object as a function of the position x of the object. 20 N x + 60 N 2 mm 0 mm < x < 2 mm 60 60 N F (x) = { 110N– 2 mm < x < 6 mm 40 4 mm 40 N -x – 40 N 4 mm 6 mm < x < 10 mm 20 2 4 8 10 Find the work W, done by the force on the object as it x (mm) travels from x = 2.00 mm to x = 9.00 mm. W. = J F(x) (N)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:A mysterious object is accelerated in a straight line across a
table by a mysterious force. The force is not constant, but
100
varies depending on the position of the object. The graph
and equations give the magnitude of the force F on the
80
object as a function of the position x of the object.
20 N
-x + 60 N
2 mm
O mm < x < 2 mm
60
60 N
F (x) :
110 N
X.
4 mm
2 mm < x < 6 mm
40
40 N
40 N
6 mm < x < 10 mm
4 mm
4
8
10
Find the work W, done by the force on the object as it
x (mm)
travels from x = 2.00 mm to x = 9.00 mm.
Wo =
J
F(x) (N)
20
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