A multi-unit process first combusts propane and then removes water from the exhaust stream. The process is designed to run at steady state. The company designing the process knows that they want to burn 70% of the propane (i.e. yield of CO₂ is only 70% of complete combustion of propane). The simple combustion reaction for propane is given below. Use the shortcut method to calculate the Degrees of Freedom around the Combustion Chamber. Stream A Rate: A-0.4 mol/hour Composition: Oxygen: A, 22.8% Nitrogen: AN-76.4% Water: Aw=?? Stream B Rate: B=0.01 mol/hour Composition: Propane: B, 100% C3H8 +502 4H20 + 3C02 Combustion Chamber Stream C Rate: C= Composition: Oxygen: Co= Nitrogen: CN= Water: Cw= Propane: C₂= CO₂: CC= Stream D Rate: D=?? Composition: Dw-100% Condenser Stream E Rate: E = ??mol/s Composition: Oxygen: E- Nitrogen: E= Water: Ew=2% Propane: E= CO₂: Ec=
A multi-unit process first combusts propane and then removes water from the exhaust stream. The process is designed to run at steady state. The company designing the process knows that they want to burn 70% of the propane (i.e. yield of CO₂ is only 70% of complete combustion of propane). The simple combustion reaction for propane is given below. Use the shortcut method to calculate the Degrees of Freedom around the Combustion Chamber. Stream A Rate: A-0.4 mol/hour Composition: Oxygen: A, 22.8% Nitrogen: AN-76.4% Water: Aw=?? Stream B Rate: B=0.01 mol/hour Composition: Propane: B, 100% C3H8 +502 4H20 + 3C02 Combustion Chamber Stream C Rate: C= Composition: Oxygen: Co= Nitrogen: CN= Water: Cw= Propane: C₂= CO₂: CC= Stream D Rate: D=?? Composition: Dw-100% Condenser Stream E Rate: E = ??mol/s Composition: Oxygen: E- Nitrogen: E= Water: Ew=2% Propane: E= CO₂: Ec=
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
A multi-unit process first combusts propane and then removes water from the exhaust stream. The
process is designed to run at steady state. The company designing the process knows that they want to
burn 70% of the propane (i.e. yield of CO2 is only 70% of complete combustion of propane). The simple
combustion reaction for propane is given below.
Use the shortcut method to calculate the Degrees of Freedom around the Combustion Chamber.
Transcribed Image Text:A multi-unit process first combusts propane and then removes water from the exhaust stream. The
process is designed to run at steady state. The company designing the process knows that they want to
burn 70% of the propane (i.e. yield of CO₂ is only 70% of complete combustion of propane). The simple
combustion reaction for propane is given below.
Use the shortcut method to calculate the Degrees of Freedom around the Combustion Chamber.
Stream A
Rate: A = 0.4 mol/hour
Composition:
Oxygen: A, 22.8%
Nitrogen: AN = 76.4%
Water: Aw = ??
Stream B
Rate: B=0.01 mol/hour
Composition:
Propane: B, 100%
C3H8 +502 →→ 4H₂O + 3C02
Combustion
Chamber
Stream C
Rate: C=
Composition:
Oxygen: Co=
Nitrogen: CN=
Water: Cw=
Propane: Cp =
CO₂: CC=
Stream D
Rate: D= ??
Composition:
Dw= 100%
Condenser
Stream E
Rate: E = ??mol/s
Composition:
Oxygen: E=
Nitrogen: EN=
Water: Ew=2%
Propane: Ep =
CO₂: Ec=
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