A motorcycle is following a car that is traveling atconstant speed on a straight highway. Initially, the carand the motorcycle are both traveling at the samespeed of 22.0 m/s, and the distance between them is85.0 m. After t₁ = 4.00 s, the motorcycle starts toaccelerate at a rate of 4.00 m/s². The motorcyclecatches up with the car at some time t₂.▶Part APart BPart C>How far does the motorcycle travel from the momentit starts to accelerate (at time t₁) until it catches upwith the car (at time t2)? Should you need to use ananswer from a previous part, make sure you use theunrounded value.Answer numerically in meters using threesignificant figures.

Answered: Image /qna-images/answer/12b8c6a7-9789-4014-a182-443b0f1e5127.jpg

Answered: A motorcycle is following a car that is…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Similar questions

Image shows the position-versus-time graphs for two objects, A and B, that are moving along the same axis.a. At the instant t = 1 s, is the speed of A greater than, less than, or equal to the speed of B? Explain.b. Do objects A and B ever have the same speed? If so, at what time or times? Explain.
An electron with an initial speed of 4.56x10^5m/s enters a linear particle accelerator that is3.50 cm long. In this section, the electron is accelerated to a final speed of 3.25x10^5m/s a) . Calculate the magnitude of the acceleration of the electron. b) Determine the time of acceleration
At an air show, a jet plane has velocity components vx =695km/h and vy =415km/h at time 4.35 s and vx =938km/h and vy =365km/h at time 7.52 s. Please answer A,B,C,D Thank you.
The acceleration of a particle is given by a = a√t 5 where A = 2.5 m/s2. At t = 0, v = 6.2 m/s and x=0. ▶ Part A Part B ▾ Part C What is the acceleration at t= 4.5 s? Express your answer using two significant figures. a = Submit Part D ——| ΑΣΦ v= Request Answer What is the speed at t = 4.5 s? Express your answer using two significant figures. ? 15| ΑΣΦ ? m/s² m/s
At time t, the position of a body moving along the s-axis is s=−t^3+12t^2−36t m. a. Find the body's acceleration each time the velocity is zero. b. Find the body's speed each time the acceleration is zero. c. Find the total distance traveled by the body from t=0 to t=3.
A scooter begins at rest at t0 = 0 seconds. The scooter starts moving, and eventually covers a distance d = 727 m, in a time tf = 189 s. In a coordinate system with north being the positive x-direction, the scooter's motion is in the northern direction A: What was the scooter's displacement in the northern direction during this period, in meters? B: What was the scooter's average velocity in in the northern direction vavg,N, in this period in meters per second? C: If the scooter's final velocity at tf was 12 m/s, what was the scooter's average acceleration in the northern direction, aavg,N, during this period in m/s2?
B3
▼ Part A A walker and a runner are on a straight horizontal section of a track. In the reference frame of the Earth, the walker has an initial position XEwi = +5.0 m and the runner has an initial position XEri+15.0 m. Three seconds later, the walker has a position XEwf = +11 m and the runner has a position XErf +3.0 m. What is the runner's velocity in the reference frame of the walker, vwr? ► View Available Hint(s) O Vwr= -2.0 m/s O Vwr=-6.0 m/s O VW-18.0 m/s O Vwr= -4.0 m/s Review Submit
The acceleration of a bus is given by ax(t) = αt, where α = 1.15 m/s3 is a constant. a. If the bus's velocity at time t1 = 1.05 s is 4.90 m/s, what is its velocity at time t2 = 2.20 s? b. If the bus's position at time t1 = 1.05 s is 6.05 m, what is its position at time t2 = 2.20 s?
A cyclist rides down a long straight road at a velocity (in m/min) given by v(t) = 400 - 20t, for 0≤t≤ 10. a. How far does the cyclist travel in the first 3 min? b. How far does the cyclist travel in the first 10 min? c. How far has the cyclist traveled when his velocity is 350 m/min?
What is the value of C if he object stops in 8.00 s after t = 0?
24. A rocket is fired upward on a straight upward trajectory at 90 degrees to the surface perfectly, starting from rest with an acceleration of +29.4 m/s² for the first 4 seconds of travel. After finishing these 4 seconds it runs out of gas but continues its upward movement on its original path for a short time. a. b. What is the maximum height it reaches? If after reaching the maximum height it is allowed to fall in free fall in a perfectly linear path towards the earth, what is its final speed just before hitting the ground? Select one: - b. a. Maximum height = 135.8 meters, final velocity = 940.8 meters/seconds Maximum height = 940.8 centimeters, final velocity = 135.8 centimeters/seconds c. Maximum height = 940.8 centimeters, final velocity = 13.58 meters/seconds d. Maximum height = 940.8 meters, final velocity = 135.8 meters/seconds

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