A molecule can have various types of energies (translational, rotational, vibrational, and electronic), the sum of which is the molecule's total energy. E trans = (n +n + n²) E rot = J (J + 1) h² 87²1 Evib = (v + ¹2 ) ₁ hv h² 8mV (2/3) In the equations, nx, ny, nz, J, and u are quantum numbers, h is Planck's constant, m is the mass of the molecule, V is the volume of the container, I is the moment of inertia of the molecule, and v is the fundamental vibration frequency. For carbon monoxide, CO, the moment of inertia is I = 1.45 x 10-46 kg-m², and the fundamental vibration frequency is v = 2130 cm-¹. Let V = 12.5 L, and let all the quantum numbers be equal to 1. Calculate the translational, rotational, and vibrational energies per mole of CO for these conditions.
A molecule can have various types of energies (translational, rotational, vibrational, and electronic), the sum of which is the molecule's total energy. E trans = (n +n + n²) E rot = J (J + 1) h² 87²1 Evib = (v + ¹2 ) ₁ hv h² 8mV (2/3) In the equations, nx, ny, nz, J, and u are quantum numbers, h is Planck's constant, m is the mass of the molecule, V is the volume of the container, I is the moment of inertia of the molecule, and v is the fundamental vibration frequency. For carbon monoxide, CO, the moment of inertia is I = 1.45 x 10-46 kg-m², and the fundamental vibration frequency is v = 2130 cm-¹. Let V = 12.5 L, and let all the quantum numbers be equal to 1. Calculate the translational, rotational, and vibrational energies per mole of CO for these conditions.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![A molecule can have various types of energies (translational, rotational, vibrational, and electronic), the sum of which is the
molecule's total energy.
E trans = (n +n + n²)
Erot = J (J + 1)
h²
87²1
Evib = (U+ 1 ) h
hv
h²
8mV (2/3)
In the equations, nx, ny, nz, J, and u are quantum numbers, h is Planck's constant, m is the mass of the molecule, V is the
volume of the container, I is the moment of inertia of the molecule, and v is the fundamental vibration frequency.
For carbon monoxide, CO, the moment of inertia is I = 1.45 x 10-46 kg-m², and the fundamental vibration frequency is
v = 2130 cm-¹. Let V = 12.5 L, and let all the quantum numbers be equal to 1.
Calculate the translational, rotational, and vibrational energies per mole of CO for these conditions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcdc18098-2fa2-4496-bd8e-c1a37e1c8dc5%2Fe2a088f9-0183-409f-a300-73c152de9252%2Flxs4ur2c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A molecule can have various types of energies (translational, rotational, vibrational, and electronic), the sum of which is the
molecule's total energy.
E trans = (n +n + n²)
Erot = J (J + 1)
h²
87²1
Evib = (U+ 1 ) h
hv
h²
8mV (2/3)
In the equations, nx, ny, nz, J, and u are quantum numbers, h is Planck's constant, m is the mass of the molecule, V is the
volume of the container, I is the moment of inertia of the molecule, and v is the fundamental vibration frequency.
For carbon monoxide, CO, the moment of inertia is I = 1.45 x 10-46 kg-m², and the fundamental vibration frequency is
v = 2130 cm-¹. Let V = 12.5 L, and let all the quantum numbers be equal to 1.
Calculate the translational, rotational, and vibrational energies per mole of CO for these conditions.
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