A mixture of gases has the following composition by mass (kg): Methanol Ethanol. Propanol Water CH3OH C₂H5OH C3H₂OH H₂O 2.00 80.0 5.00 20.0 a) What is the mixture composition in mass fractions? b) What is the mixture composition in mole fractions? Atomic masses (g/mol) are: 1, 12, and 16 for H, C, and O, respectively. c) What is the average molecular weight of this mixture? d) What is the mole fraction of propanol if all of the water is removed?
A mixture of gases has the following composition by mass (kg): Methanol Ethanol. Propanol Water CH3OH C₂H5OH C3H₂OH H₂O 2.00 80.0 5.00 20.0 a) What is the mixture composition in mass fractions? b) What is the mixture composition in mole fractions? Atomic masses (g/mol) are: 1, 12, and 16 for H, C, and O, respectively. c) What is the average molecular weight of this mixture? d) What is the mole fraction of propanol if all of the water is removed?
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:A mixture of gases has the following composition by mass (kg):
Methanol
Ethanol
Propanol
Water
CH3OH
C₂H5OH
C3H7OH
H₂O
2.00
80.0
5.00
20.0
a) What is the mixture composition in mass fractions?
b) What is the mixture composition in mole fractions? Atomic masses (g/mol) are: 1, 12, and
16 for H, C, and O, respectively.
c) What is the average molecular weight of this mixture?
d) What is the mole fraction of propanol if all of the water is removed?
Expert Solution

Step 1
Composition of Mixture of Gases by mass (Kg) are given as:
1) Methanol=2 kg
2) Ethanol=80 kg
3)Propanol=5 kg
4) Water=20 kg
Step by step
Solved in 5 steps

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