A mixture of gases contains 3.16 g of 03, 7.86 g of H2, and 2.79 g of SF6. What is the partial pressure in atm of each component of this mixture if it is held in a 25.9-L vessel at 23.0 °C?Use R = 0.0821 L-atm/mol-K as the value of the gas constant.O a) P(03) = 14.3 atm, P(H2) = 0.241 atm, and P(SFs) = 49.1 atm.O b) P(03) = 41.4 atm, P(H2) = 2450 atm, and P(SF6) = 12.0 atm.O c) P(03) = 0.498 atm, P(H2) = 1.24 atm, and P(SF6) = 0.440 atm.O d) P(03) = 0.337 atm, P(H2) = 0.136 atm, and P(SF6) = 0.382 atm.O e) P(03) = 0.0618 atm, P(H2) = 3.65 atm, and P(SFs) = 0.0179 atm.

Partial pressure of a gas is its pressure in a mixture of gases. The pressure of each gas can be…

Answered: A mixture of gases contains 3.16 g of…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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