A mixture of 0.56 g BaCl2.2H2O(molar mass = 244.2g/mol) and1.44 g of NagPO4.12H20 (molarmass = 380.2g/mol) was dissolvedin water. Calculate the moles of%3Dunreacted species that excess.2NasPO, + 3BaCl2 → Bag(PO4)2(s) +6NACIO a. 3.78 x 10 mol. BaCl2O b. 1.48 x 10 mol. BaCl2Oc. 1.48 x 10³ mol. Na3PO4O d. 2.25 x 10 mol. NagPO4O e. 2.25 x 10 mol. BaCl2

Given reaction:2Na3PO4 + 3BaCl2→ Ba3PO42s + 6NaClMass of BaCl2 = 0.56 gMass of Na3PO4 = 1.44 g

A mixture of 0.56 g BaCl2.2H0 (molar mass = 244.2g/mol) and 1.44 g of NagPO412H20 (molar %3D mass = 380.2g/mol) was dissolved in water. Calculate the moles of unreacted species that excess. %3D 2NagPO, + 3BaCl2 → Baş(PO4)2 (s) + 6NACI

A mixture of 0.56 g BaCl2.2H0 (molar mass = 244.2g/mol) and 1.44 g of NagPO412H20 (molar %3D mass = 380.2g/mol) was dissolved in water. Calculate the moles of unreacted species that excess. %3D 2NagPO, + 3BaCl2 → Baş(PO4)2 (s) + 6NACI

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

A mixture of 0.56 g BaCl2.2H2O
(molar mass = 244.2g/mol) and
1.44 g of NagPO4.12H20 (molar
mass = 380.2g/mol) was dissolved
in water. Calculate the moles of
%3D
unreacted species that excess.
2NasPO, + 3BaCl2 → Bag(PO4)2
(s) +6NACI
O a. 3.78 x 10 mol. BaCl2
O b. 1.48 x 10 mol. BaCl2
Oc. 1.48 x 10³ mol. Na3PO4
O d. 2.25 x 10 mol. NagPO4
O e. 2.25 x 10 mol. BaCl2

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