A mixture of 0.05087 mol of C₂H₂, 0.08092 mol of N₂, 0.06764 mol of NH3, and 0.01848 mol of CHg is placed in a 1.0-L steel pressure vessel at 1147 K. The following equilibrium is established: 3 C₂H₂(g) + 1 N₂(g) = 2 NH3(g) + 1 CH₂(9) At equilibrium 0.006669 mol of CH is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of C₂H4, N2, NH3, and C6H6. Peo(C₂Ha) = Pea(N₂) = Peg(NH)) = Pea(CH) - (b) Calculate Kp for this reaction. Kp =
A mixture of 0.05087 mol of C₂H₂, 0.08092 mol of N₂, 0.06764 mol of NH3, and 0.01848 mol of CHg is placed in a 1.0-L steel pressure vessel at 1147 K. The following equilibrium is established: 3 C₂H₂(g) + 1 N₂(g) = 2 NH3(g) + 1 CH₂(9) At equilibrium 0.006669 mol of CH is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of C₂H4, N2, NH3, and C6H6. Peo(C₂Ha) = Pea(N₂) = Peg(NH)) = Pea(CH) - (b) Calculate Kp for this reaction. Kp =
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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