A mixture of 0.05087 mol of C₂H₂, 0.08092 mol of N₂, 0.06764 mol of NH3, and 0.01848 mol of CHg is placed in a 1.0-L steel pressure vessel at 1147 K. The following equilibrium is established: 3 C₂H₂(g) + 1 N₂(g) = 2 NH3(g) + 1 CH₂(9) At equilibrium 0.006669 mol of CH is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of C₂H4, N2, NH3, and C6H6. Peo(C₂Ha) = Pea(N₂) = Peg(NH)) = Pea(CH) - (b) Calculate Kp for this reaction. Kp =

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A mixture of 0.05087 mol of C₂H4, 0.08092 mol of N₂, 0.06764 mol of NH3, and 0.01848 mol of CH is placed in a 1.0-L steel pressure
vessel at 1147 K. The following equilibrium is established:
3 C₂H4(9) + 1 N₂(9) 2 NH3(9) + 1 CHg(9)
At equilibrium 0.006669 mol of CeHe is found in the reaction mixture.
(a) Calculate the equilibrium partial pressures of C₂H4, N2, NH3, and C6H6
Pea(C₂H4)=
Peq(N₂) =
Peg(NH3)
Peq(C6H6)
(b) Calculate Kp for this reaction.
Kp =
Transcribed Image Text:A mixture of 0.05087 mol of C₂H4, 0.08092 mol of N₂, 0.06764 mol of NH3, and 0.01848 mol of CH is placed in a 1.0-L steel pressure vessel at 1147 K. The following equilibrium is established: 3 C₂H4(9) + 1 N₂(9) 2 NH3(9) + 1 CHg(9) At equilibrium 0.006669 mol of CeHe is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of C₂H4, N2, NH3, and C6H6 Pea(C₂H4)= Peq(N₂) = Peg(NH3) Peq(C6H6) (b) Calculate Kp for this reaction. Kp =
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