A mixture of 0.04096 mol of C₂H6, 0.05994 mol of N₂, 0.04520 mol of NH3, and 0.02898 mol of C₂H4 is placed in a 1.0-L steel pressure vessel at 1900 K. The following equilibrium is established: 3 C₂H6(9) + 1 N₂(9)=2 NH3(g) + 3 C₂H₂(9) At equilibrium 0.02365 mol of C₂H4 is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of C₂H6, N₂, NH3, and C₂H₁. Peq(C₂H)= Peq(N₂) = Peg(NHy) = Peq(C₂H4) (b) Calculate Kp for this reaction. Kp

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A mixture of 0.04096 mol of C₂H6, 0.05994 mol of N₂, 0.04520 mol of NH3, and 0.02898 mol of C₂H4 is placed in a 1.0-L steel
pressure vessel at 1900 K. The following equilibrium is established:
3 C₂H6(9) + 1 N₂(9)=2 NH3(g) + 3 C₂H4 (9)
At equilibrium 0.02365 mol of C₂H4 is found in the reaction mixture.
(a) Calculate the equilibrium partial pressures of C₂H6, N₂, NH3, and C₂H₁.
Peq(C₂H6)
Peq(N₂) =
Peq(NH3)=
Peq(C₂H4)=
(b) Calculate Kp for this reaction.
Kp =
Transcribed Image Text:A mixture of 0.04096 mol of C₂H6, 0.05994 mol of N₂, 0.04520 mol of NH3, and 0.02898 mol of C₂H4 is placed in a 1.0-L steel pressure vessel at 1900 K. The following equilibrium is established: 3 C₂H6(9) + 1 N₂(9)=2 NH3(g) + 3 C₂H4 (9) At equilibrium 0.02365 mol of C₂H4 is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of C₂H6, N₂, NH3, and C₂H₁. Peq(C₂H6) Peq(N₂) = Peq(NH3)= Peq(C₂H4)= (b) Calculate Kp for this reaction. Kp =
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