A mixture of 0.01586 mol of H₂O, 0.01788 mol of CH4, 0.04625 mol of CO, and 0.07019 mol of H₂ is placed in a 1.0-L steel pressure vessel at 1567 K. The following equilibrium is established: 1 H₂O(g) + 1 CH4 (9) 1 CO(g) + 3 H₂(g) At equilibrium 0.005674 mol of H₂O is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of H₂O, CH4, CO, and H₂. Peq(H₂O) = Peq(CH4) = [ Peq(CO) = Peq(H₂) = (b) Calculate Kp for this reaction. Kp =

A mixture of 0.01586 mol of H₂O, 0.01788 mol of CH4, 0.04625 mol of CO, and 0.07019 mol of H₂ is placed in a 1.0-L steel pressure vessel at 1567 K. The following equilibrium is established: 1 H₂O(g) + 1 CH4 (9) 1 CO(g) + 3 H₂(g) At equilibrium 0.005674 mol of H₂O is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of H₂O, CH4, CO, and H₂. Peq(H₂O) = Peq(CH4) = [ Peq(CO) = Peq(H₂) = (b) Calculate Kp for this reaction. Kp =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A mixture of 0.01586 mol of H₂O, 0.01788 mol of CH4, 0.04625 mol of CO, and 0.07019 mol of H₂ is placed in a 1.0-L steel pressure vessel at 1567 K. The following equilibrium is established:
1 H₂O(g) + 1 CH4(9) — 1 CO(g) + 3 H₂(g)
At equilibrium 0.005674 mol of H₂O is found in the reaction mixture.
(a) Calculate the equilibrium partial pressures of H₂O, CH4, CO, and H₂.
Peq(H₂O)=
Peq(CH4) =
Peq (CO) =
Peq(H₂) =
=
(b) Calculate Kp for this reaction.
Kp
=

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