A mirror has f = −1.50 m. A real object is 0.850 m away from the mirror. Where is the image?
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A mirror has f = −1.50 m. A real object is 0.850 m away from the mirror. Where is the image?
can you please also include a picture to help me better understand? thank you
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- please help: A magician wishes to create the illusion of a 2.76-m-tall elephant. He plans to do this by forming a virtual image of a 51.5-cm-tall model elephant with the help of a spherical mirror. A) If the model must be placed 3.15 m from the mirror, what radius of curvature is needed? B) How far from the mirror will the image be formed?The convex mirror shown in the drawing forms a virtual image of an arrow at x = x2 = 24.9 cm. The image of the tip of the arrow is located at y = y2 = 6.8 cm. The magnitude of the focal length of the convex mirror is 47 cm.A 4.4-cm tall.statue is 28 cm in front of a concave mirror having a focal length of magnitude 20 cm. Draw the ray diagrams and determine the characteristics of the image graphically and analytically. - where is the image?, how tall the image is? Note: Submit the drawing along with your solution in the corresponding folder!
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- An object with a height of 39 cm is placed 1.6 m in front of a convex mirror with a focal length of -0.75 m. Part A Determine the approximate location of the image using a ray diagram. Express your answer using two significant figures. ΑΣφ d; = m behind the mirror Submit Request Answer Part B Determine the approximate size of the image using a ray diagram. Express your answer using two significant figures. ΑΣφ hi = cm Submit Request AnswerAn object is 15 cm in front of a convex mirror with a focal length of 30 cm. (a) Use ray tracing to find the position of the image. (b) Calculate the image position using the mirror equation. Compare with your ray tracing answers in part (a). (c) What is the magnification? Is the image real or virtual? upright or inverted? h